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Marianna [84]
3 years ago
7

11. What do foliated and un-foliated mean in metamorphic rocks?

Physics
1 answer:
Olegator [25]3 years ago
6 0

They are two types of metamorphic rocks which differ on the basis of formation and appearance.

<u>Explanation</u>:

  • Foliated metamorphic rocks are a type of metamorphic rocks which appear like layers which is caused due to heat exposure and pressure.
  • They are formed due to high pressures.
  • Examples are phyllite, slate, schist
  • Non-foliated metamorphic rocks do not have such a layered appearance.
  • They are formed due to low pressures and also because of contact metamorphism. This is why they are mostly called as hornfels.
  • Examples are hornfels, marble
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A toy cannon launches a 46-g golf ball straight up into the air with a kinetic energy of 6.8 J. What must the
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Answer : The correct option is, (C) 17 m/s

Explanation :

Formula used :

K.E=\frac{1}{2}mv^2

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Now put all the given values in the above formula, we get:

K.E=\frac{1}{2}mv^2

6.8J=\frac{1}{2}\times 0.046kg\times v^2

6.8kg.m^2/s^2=\frac{1}{2}\times 0.046kg\times v^2

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A car accelerates in the +x direction from rest with a constant acceleration of a1 = 1.76 m/s2 for t1 = 20 s. At that point the
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Answer:

(a)v_1 = a_1t_1 = 1.76 t_1

(b) It won't hit

(c) 110 m

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v_1 = v_0 + a_1t_1 = 0 +1.76t_1 = 1.76t_1

(b) The velocity of the car before the driver begins braking is

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The driver brakes hard and come to rest for t2 = 5s. This means the deceleration of the driver during braking process is

a_2 = \frac{\Delta v_2}{\Delta t_2} = \frac{v_2 - v_1}{t_2} = \frac{0 - 35.2}{5} = -7.04 m/s^2

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s_2 = v_1t_2 + a_2t_2^2/2

s_2 = 35.2*5 - 7.04*5^2/2 = 88 m

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s_1 = a_1t_1^2/2 = 1.76*20^2/2 = 352

So the total distance from rest to stop is 352 + 88 = 440 m < 550 m so the car won't hit the limb

(c) The distance from the limb to where the car stops is 550 - 440 = 110 m

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