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Mariulka [41]
3 years ago
12

Calculate the pressure produced by a force of 1500 N acting on an area of 6 m​2​

Physics
2 answers:
S_A_V [24]3 years ago
5 0
Answer: 250 Pascals

Using the formula to calculate for the pressure: P=F/A
P(pressure)
F(force)
A(area)

You can apply it here:
P=F/A
P= 1500 N/ 6m^2
P= 250 Pa
Aleksandr [31]3 years ago
4 0

Answer:

250 N/m²

Explanation:

Pressure = Force / Area

P = 1500 / 6

P = 250

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At the nose of a missile in flight, the pressure and temperature are 5.6 atm and 850°R, respectively. Calculate the density and
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To solve this problem we will apply the definition of the ideal gas equation, where we will clear the density variable. In turn, the specific volume is the inverse of the density, so once the first term has been completed, we will simply proceed to divide it by 1. According to the definition of 1 atmosphere, this is equivalent in the English system to

1atm = 2116lb/ft^2

The ideal gas equation said us that,

PV = nRT

Here,

P = pressure

V = Volume

R = Gas ideal constant

T = Temperature

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Then

\frac{n}{V} = \frac{P}{RT}

The amount of substance per volume is the density, then

\rho = \frac{P}{RT}

Replacing with our values,

\rho = \frac{5.6*2116}{1716*850}

\rho = 0.00812slug/ft^3

Finally the specific volume would be

v = \frac{1}{\rho}

v = 123ft^3/slug

6 0
3 years ago
Four pairs of objects have the masses as described below, along with the distances between
lord [1]

Answer:

<h2>Mass of 1 Kg and 2 Kg, 1 meters apart.</h2>

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The gravitational force is defined as

F=G\frac{m_{1} m_{2} }{r^{2} }

By definition, the gravitational force depends directly on the product of the masses and indirectly on the distance between the masses, which means the further they are, the less gravitational force would be. And, the greater the masses, the greater the gravitational force.

Among the options, the pair that would have the greatest gravitational force is  Mass of 1 Kg and 2 Kg, with 1 meter between them.

Notice that the last choice includes the same masses but with a greater distance between them, that means it would be a weaker graviational force.

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7 0
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A cabbie is trying to stop when he notices a fare is whistling them over. The
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  • Velocity=v

\boxed{\sf K.E=\dfrac{1}{2}mv^2}

\\ \sf\longmapsto 18750=\dfrac{1}{2}2100v^2

\\ \sf\longmapsto 18750=1050v^2

\\ \sf\longmapsto v^2=\dfrac{18750}{1050}

\\ \sf\longmapsto v^2=17.85m^2

\\ \sf\longmapsto v=\sqrt{17.85}

\\ \sf\longmapsto v=4.1m/s

7 0
3 years ago
Your body is receiving backround radiation all the tim. Explain
adoni [48]
The uniform microwave radiation remaining from the Big Bang.


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A standing wave of the third overtone is induced in a stopped pipe, 2.5 m long. The speed of sound is The frequency of the sound
NemiM [27]

Answer:

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Explanation:

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You replace the values of n, L and vs in order to calculate the frequency:

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hence, the frequency of the third overtone is 102 Hz

8 0
3 years ago
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