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topjm [15]
3 years ago
15

What happens when sodium Hydroxide reacts with Hydrochloric acid?​

Physics
2 answers:
maxonik [38]3 years ago
7 0

As we know that when base react with acid to form salt and water. This type of reaction is known as Neutralization reaction.

When Sodium Hydroxide reacts with Hydrochloric acid to form Sodium Chloride and Water.

As a result of neutralization reaction Sodium Chloride and Water is formed.

svet-max [94.6K]3 years ago
4 0

When Sodium Hydroxide reacts with Hydrochloric Acid, it can be represented by the chemical equation below:

NaOH + HCl -> NaCl + H2O

So Sodium Chloride and water will be formed.

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How long will it take a ball to roll 10 meters along the floor at a speed of 0.5m/s
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1 year ago
2.) The lob in tennis is an effective tactic when your opponent is near the net. It consists of lofting the ball over his/her he
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Answer:

The minimum average speed the opponent must move so that he is in position to hit the ball is approximately 5.79 m/s

Explanation:

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The direction in which the ball is launched = 50° above the horizontal

The location of the other tennis player when the ball is launched = 10 m from the ball

The time at which the other tennis player begins to run = 0.3 seconds after the ball is launched

The height at which the ball is hit back = 2.1 m above the height from which the ball is launched

The vertical position, 'y', at time, 't', of a projectile motion is given as follows;

y = (u·sinθ)·t - 1/2·g·t²

When y = 2.1 m, we have;

2.1 = (15·sin(50°))·t - 1/2·9.8·t²

∴ 4.9·t² - (15·sin(50°))·t + 2.1 = 0

Solving with the aid of a graphing calculator function, we get;

t = 0.199776187257 s or t = 2.14525782198 s

Therefore, the ball is at 2.1 m above the start point on the other side of the court at t ≈ 2.145 seconds

The horizontal distance, 'x', the ball travels at t ≈ 2.145 seconds is given as follows;

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The horizontal distance the ball travels at t ≈ 2.145 seconds, x ≈ 20.682 m

Therefore, we have;

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The distance the other player has to run, d = 20.682 m - 10 m = 10.682 m

The minimum average speed the other player has to move with, v_s = d/t₂

∴ v_s = 10.682 m/(1.845 s) ≈ 5.78970189702 m/s ≈ 5.79 m/s

The minimum average speed the opponent must move so that he is in position to hit the ball, v_s ≈ 5.79 m/s.

5 0
3 years ago
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