Where you get all the steps when you finally get a reaction . Ex, vinegar and baking soda you go step by step.
Hope this helps :)
Answer:
The distance on the screen between the first-order bright fringes for each wavelength is 3.17 mm.
Explanation:
Given that,
Wavelength of red = 660 nm
Wavelength of blue = 470 nm
Separated d= 0.30 mm
Distance between screen and slits D= 5.0 m
We need to calculate the distance for red wavelength
Using formula for distance

Where, D = distance between screen and slits
d = separation of slits
Put the value into the formula


For blue wavelength,
Put the value into the formula again


We need to calculate the distance on the screen between the first-order bright fringes for each wavelength
Using formula for distance



Hence, The distance on the screen between the first-order bright fringes for each wavelength is 3.17 mm.
Answer:
The mass's acceleration is 5 m/s^2 in the minus X direction and 9,8 m/s^2 in the minus Y direction.
Explanation:
By applying the second Newton's law in the X and Y direction we found that in the minus X direction an external force of 10 N is exerted, while in the minus Y direction the gravity acceleration is acting:
X-direction balance force:
Y-direction balance force:
Where ax and ay are the components of the respective acceleration and m is the mass. By solving for each acceleration:
Note that for the second equation above the mass is cancelled and, the Y direction acceleration is minus the gravity acceleration:
For the x component aceleration we must replace the Newton unit:

Answer:
Explanation:
90 rpm = 90 / 60 rps
= 1.5 rps
= 1.5 x 2π rad /s
angular velocity of flywheel
ω = 3π rad /s
Let I be the moment of inertia of flywheel
kinetic energy = (1/2) I ω²
(1/2) I ω² = 10⁷ J
I = 2 x 10⁷ / ω²
=2 x 10⁷ / (3π)²
= 2.2538 x 10⁵ kg m²
Let radius of wheel be R
I = 1/2 M R² , M is mass of flywheel
= 1/2 πR² x t x d x R² , t is thickness , d is density of wheel .
1/2 πR⁴ x t x d = 2.2538 x 10⁵
R⁴ = 2 x 2.2538 x 10⁵ / πt d
= 4.5076 x 10⁵ / 3.14 x .1 x 7800
= 184
R= 3.683 m .
diameter = 7.366 m .
b ) centripetal accn required
= ω² R
= 9π² x 3.683
= 326.816 m /s²
Answer:
The work done by gravity during the roll is 490.6 J
Explanation:
The work (W) is:

<em>Where</em>:
F: is the force
d: is the displacement = 20 m
The force is equal to the weight (W) in the x component:

<em>Where:</em>
m: is the mass of the bowling ball = 5 kg
g: is the gravity = 9.81 m/s²
θ: is the degree angle to the horizontal = 30°
Now, we can find the work:
Therefore, the work done by gravity during the roll is 490.6 J.
I hope it helps you!