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Ket [755]
3 years ago
6

STOP WHAT UR DOING!!! TAKE A MOMENT TO THINK ABOUT THESE!!

Physics
1 answer:
dolphi86 [110]3 years ago
4 0

Answer:

lol

can i have brainllest

Explanation:

Think of this how can a camera have a circler lens but take rectangular photos

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Which observation did researchers make in studies on separated twins ?
choli [55]
Depending on whether they where conjoined initially, or where born separately really changes the answer of this question. Although studies show that twins generally have a kinetic link, more practical research says that twins are 25% more likely to both be left handed, which is a recessive gene, they are also more likely to die in child birth, twins are more likely to understand and be biligual, along with many other advantages twins may have.
7 0
3 years ago
Where is the Oort Cloud located?
Nonamiya [84]

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c

Explanation:

8 0
3 years ago
A sound system is being set up in a gazebo in a park. It needs to produce music so that everyone can hear it. How much power wou
Agata [3.3K]

Answer:

Power of the speakers = 1.57 \times 10^{-6} W

Explanation:

There are speakers setup in a park and we have to find the power it would require to have intensity of sound to be 10^{-8} W/m^2 at a distance of 5 meter.

In one dimension the intensity is constant as the wave travels. In two or three dimensions, however, the intensity decreases as you get further from the source.

Intensity is inversely proportional to the square of the distance from the point of sound production.

Here area = 2\times \pi \times r^{2}

area = 157 m^{2}

Intensity = \frac{Power}{Area}

Power = intensity \times area

Power = 10^{-8} \times 157Power = 1.57 [tex]\times 10^{-6} W

7 0
3 years ago
Refer to the figure for this question: Four particles form a square. the charges are q1=q4=Q and q2=q3=q. (Part A) What is Q/q i
nikitadnepr [17]
Draw a vector diagram. The net force on particle 1 = F12 + F13 + F14 These forces have to be added as vectors. 
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By symetry this is the same as F13 F13 = -kQq /( a^2 * sqrt(2) ) 
F14 = -kQQ / (Sqrt(2)*a) ^ 2 
For net force on particle 1 : 
F12+F13+F14 = 0 -2kQq /( a^2 * sqrt(2) ) + -kQQ / (Sqrt(2)*a) ^ 2 = 0 
Some simple manipulation should give you : 
Q/q = -2 sqrt(2) 
4 0
3 years ago
Read 2 more answers
Help<br> help <br> help<br> plssss
Flauer [41]

Answer:

sorry i don't no

i promise i will help you later

now i am also in trouble now

nobody helps me

4 0
3 years ago
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