All categories

3 years ago

STOP WHAT UR DOING!!! TAKE A MOMENT TO THINK ABOUT THESE!!

Physics

1 answer:

dolphi86 [110]3 years ago

4 0

Answer:

lol

can i have brainllest

Explanation:

Think of this how can a camera have a circler lens but take rectangular photos

You might be interested in

What is the formula you use to determine the gravitational potential energy of a object

kozerog [31]

Gravitational potential energy, relative to some level =

   (mass of the object)
times
       (height above the reference level)
times
   (acceleration due to gravity) .

4 0

3 years ago

Elsie is finishing second grade. If she goes to school 147 day per year and she have 10 years of school left, how many days of s

ICE Princess25 [194]

Answer:

1,323 days left

Explanation:

147 x 10 = 1,470

1470 - 147 = 1,323

Hopefully this helps you :)

pls mark brainlest ;)

6 0

3 years ago

Which statement describes the difference between ionic bonds and Van der

Afina-wow [57]

Answer:

C. lonic bonds involve the transfer of electrons between ions, while

Van der Waals forces involve the attraction of nonpolar molecules.

Explanation:

Just did it

4 0

2 years ago

Newton's first law of motion states that an object at rest will stay at rest unless acted

Ludmilka [50]

Answer:

All are examples

Explanation:

Football acted upon by the force of the foot

Bicycle acted on by imbalanced force of gravity

Friction of dirt on player slows his run.

stick and water acted on by imbalanced force of gravity

7 0

2 years ago

A marble runs off the edge of a table that is 1.5 m high and the marble lands 0.50 m from the base of the table. a. How much tim

Free_Kalibri [48]

Answer:

t = 0.55[sg]; v = 0.9[m/s]

Explanation:

In order to solve this problem we must establish the initial conditions with which we can work.

y = initial elevation = - 1.5 [m]

x = landing distance = 0.5 [m]

We set "y" with a negative value, as this height is below the table level.

in the following equation (vy)o is equal to zero because there is no velocity in the y component.

therefore:

$y = (v_{y})_{o}*t - \frac{1}{2} *g*t^{2}\\ where:\\(v_{y})_{o}=0[m/s]\\t = time [sg]\\g = gravity = 9.81[\frac{m}{s^{2}}]\\ -1.5 = 0*t -4.905*t^{2} \\t = \sqrt{\frac{1.5}{4.905} } \\t=0.55[s]$

Now we can find the initial velocity, It is important to note that the initial velocity has velocity components only in the x-axis.

$(v_{x} )_{o} = \frac{x}{t} \\(v_{x} )_{o} = \frac{0.5}{0.55} \\(v_{x} )_{o} =0.9[m/s]$

3 0

3 years ago