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UNO [17]
3 years ago
10

When a person plucks a guitar string, the number of half wavelengths that fit into the length of the string determines the _____

__ of the sound produced.
Physics
1 answer:
Vedmedyk [2.9K]3 years ago
8 0

Answer:

Frequency

Explanation:

Each half wavelength has a point of largest amplitude (aka a node). Depending on the wavelength each node oscillates at a certain rate of swings per unit of time. The latter is referred to as frequency and measure in Hertz [Hz].

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A car is accelerated from 40 m/s to 48 m/s in 6.5 seconds. What is the magnitude of the car’s
pantera1 [17]

Answer:

Explanation:

AVerage acceleration is the cjange in velocity with time

a = v-u/t

v is the final velocity = 48m/s

u is the initial velocity = 40m/s

t is the time = 6.5s

a = 48-40/6.5

a = 8/6.5

a = 1.23m/s²

Hence the magnitude of the car’s  average acceleration during this period is 1.23m/s²

4 0
3 years ago
Please give answer with solution​
UNO [17]
250 m. for a longer explanation or solution look at this article, i’m sorry.
https://www.quora.com/A-projectile-is-thrown-so-it-travels-a-maximum-range-of-1000m-How-high-will-it-rise
3 0
3 years ago
Introduction to Symbolic Answers, Part B, Enter the expression 2cos2(θ)−1, where θ is the lowercase Greek letter theta.
lesantik [10]
2cos2(o)-1    is the answer
4 0
4 years ago
A horizontal object-spring system oscillates with an amplitude of 2.8 cm. If the spring constant is 275 N/m and object has a mas
Lisa [10]

Answer:

(a) the mechanical energy of the system, U = 0.1078 J

(b) the maximum speed of the object, Vmax = 0.657 m/s

(c) the maximum acceleration of the object, a_max = 15.4 m/s²

Explanation:

Given;

Amplitude of the spring, A = 2.8 cm = 0.028 m

Spring constant, K = 275 N/m

Mass of object, m = 0.5 kg

(a) the mechanical energy of the system

This is the potential energy of the system, U = ¹/₂KA²

U = ¹/₂ (275)(0.028)²

U = 0.1078 J

(b) the maximum speed of the object

V_{max} =\omega*A=  \sqrt{\frac{K}{M} } *A\\\\V_{max} = \sqrt{\frac{275}{0.5} } *0.028\\\\V_{max} = 0.657 \ m/s

(c) the maximum acceleration of the object

a_{max} = \frac{KA}{M} \\\\a_{max} = \frac{275*0.028}{0.5}\\\\a_{max} = 15.4 \ m/s^2

6 0
3 years ago
Spiders may "tune" strands of their webs to give an enhanced response at frequencies corresponding to the frequencies at which d
Bingel [31]

Answer:

0.0000167283525619 N

Explanation:

\rho = Density of silk = 1300 kg/m³

d = Diameter = 0.002 mm

r = Radius = 0.001 mm

l = Length = 16 cm

f = Frequency = 200 Hz

Mass of the string is

m=\rho V\\\Rightarrow m=\rho Al\\\Rightarrow m=1300\times \pi (0.001\times 10^{-3})^2\times 0.16\\\Rightarrow m=6.5345127195\times 10^{-10}\ kg

Frequency is given by

f=\dfrac{1}{2l}\sqrt{\dfrac{T}{m/l}}\\\Rightarrow T=4lf^2m\\\Rightarrow T=4\times 0.16\times 200^2\times 6.5345127195\times 10^{-10}\\\Rightarrow T=0.0000167283525619\ N

The tension on the string is 0.0000167283525619 N

3 0
3 years ago
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