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Liula [17]
3 years ago
15

determine the lone pairs and electron and electron densities in C in CH4, O in CH3OH, F in PH2F, N in NOH

Chemistry
1 answer:
Crazy boy [7]3 years ago
6 0
In CH4, C has no lone pairs, the electron density is zero since it is equally distributed. 
in CH3OH, O has 2 lone pairs.
In PH2F, F has 3 lone pairs
In NOH, N has 1 lone pair, in this case, oxygen has more lone pairs than N as such the electron density of oxygen is higher than that of nitrogen.

*Reference pictures to see how they each connect. 

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What is the difference in mass between 3.01×10^24 atoms of gold and a gold bar with the dimensions 6.00 cm X 4.25 cm X 2.00 cm
Zanzabum

Answer:

The difference in mass between 3.01×10^24 atoms of gold and a gold bar with the dimensions 6.00 cm X 4.25 cm X 2.00 cm is :

<u>Difference</u>  <u>in mass</u> =<u> 985.32 - 984.5 = 0.82 g</u>

Explanation:

<u>Part I :</u>

n =\frac{3.01\times 10^{24}}{6.022\times 10^{23}}

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(Note : You can also take n = 5 mole )

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<u>Part II :</u>

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Volume of the cuboid = length\times breadth\times height

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Using formula,

Density = \frac{mass}{Volume}

Mass = Density\times Volume

Mass = 19.32 \times 51

Mass = 985.32 g

So, A  gold bar with the dimensions 6.00 cm X 4.25 cm X 2.00 cm has mass of <u>985.32 g</u>

<u>Difference</u>  <u>in mass</u> =<u> 985.32 - 984.5 = 0.82 g</u>

3 0
3 years ago
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3 years ago
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