Ask question

Ask question

All categories

2 years ago

8

2.38g of black copper(iii) oxide is completely reduced to by hydrogen to give copper and water. What are the number of atoms of

copper formed? Equation for this reaction:
Cu203 + 3H2 → 2Cu + 3H20

1 answer:

OleMash [197]2 years ago

6 0

Explanation:

here is the answer bae. Feel free to ask for more

You might be interested in

Please help explain and don't answer if you don't know. thank you

ipn [44]

Answer:

The group 18 elements are helium (He), neon (Ne), argon (Ar), krypton (Kr), xenon (Xe), and radon (Rn). These elements are non-reactive and are called noble gases as they have their outermost orbit complete. Due to stable electronic configuration they hardly react with other elements.The name comes from the fact that these elements are virtually unreactive towards other elements or compounds.The group 18 elements are called noble or inert gases. As the name suggests these are inert because chemically they are very less reactive or not at all reactive.The full valence electron shells of these atoms make the noble gases extremely stable.

5 0

2 years ago

Volume occupied 3.52x10^32 moluchles<br>of Mathane (CH4)<br>1) At STP

Naddika [18.5K]

Answer:

volume = 13097674418.528dm³

Explanation:

n = (3.52)*10^32/(6.02)*10^23)

n = (584717607.97)

n = volume /molar volume

molar volume at stp = 22.4dm³

volume= 584717607.97 x 22.4

volume = 13097674418.528dm³

6 0

2 years ago

A scuba diver that ascends to the surface too quickly can experience decompression sickness, which occurs when nitrogen that dis

Butoxors [25]

Answer:

The factor that will change the volume of the diver's lungs upon reaching the surface is 4

Explanation:

Given data:

Pressure increases 1 atm = 101.325 kPa

34 ft = 10.3632 m

Depth of 102 ft = 31.0896 m

Question: What factor will the volume of the diver's lungs change upon arrival at the surface, V₂/V₁ = ?

The pressure at 31.0896 m:

$P_{1} =101.325+(\frac{31.0896}{10.3632} *101.325)=405.3kPa$

The factor will the volume of the diver's lungs change upon arrival at the surface:

$\frac{V_{2}}{V_{1} } =\frac{P_{1}}{P_{2}} =\frac{405.3}{101.325} =4$

5 0

2 years ago

To make a sarurated solution, 36 g of sodium chloride is dissolved in 100 g of water at 293 k . Find its concentration at this t

nexus9112 [7]

Answer:

The answer is " $26.47\%$ "

Explanation:

Sodium chloride solute mass $=36 \ g$

Solvent water mass $=100\ g$

Calculating the solution mass = Solute mass + solvent mass

$= 36\ g +100\ g\\\\ = 136\ g\\\\$

Calculating the percentage of concentration:

$= \frac{solute\ mass}{solvent\ mass} \times 100\\\\=\frac{36\ grm}{136\ grm} \times 100\\\\=0.2647 \times 100\\\\=26.47 \%$

3 0

2 years ago

If I combine atoms then I must be performing which process?

Evgesh-ka [11]

The answer is fusion. hope this helps!

6 0

2 years ago

Read 2 more answers