1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Basile [38]
3 years ago
11

Solid silver is added to copper (ii) sulfate. does a single replacement reaction occur, and if so what is the correct chemical e

quation for this reaction? 2ag + cuso4 yields no reaction ag + cuso4 yields agso4 + cu ag + cuso4 yields ag2so4 + cu 2ag + cuso4 yields ag2so4 + cu
Chemistry
1 answer:
ivanzaharov [21]3 years ago
3 0
No reaction would occur because copper is more active than silver and silver would be unable to donate electrons to copper.
You might be interested in
To do an experiment with the peptide H-A-P-P-Y you need to make two buffers. One where the peptide has a net negative charge (Bu
nata0808 [166]

Answer:

Buffer A: pH 5.25; 2.82 mol of acetate for every 1 mol of acetic acid

Buffer B: pH 9.25; 11.2 mol of bicarbonate for every 1 mol of carbonate

Explanation:

The pI of a protein is the pH at which it has a net charge of zero.

The protein has a positive charge below the pI and a negative charge above it.

Since pI = 7.25, let's make one buffer at pH = 5.25 and one at pH 9.25.

1. Preparation of pH 5.25 buffer

(a) Choose the conjugate pair

We should choose a buffer with pKₐ close to 5.25.

Acetic acid has pKₐ = 4.8, so let's make acetate buffer.

(b) Protocol for preparation

We can use the Henderson-Hasselbalch equation to get the acid/base ratio.

\begin{array}{rcl}\text{pH} & = & \text{pK}_{\text{a}} + \log \left(\dfrac{[\text{A}^{-}]}{\text{[HA]}}\right )\\\\5.25& = & 4.8 +\log \left(\dfrac{[\text{A}^{-}]}{\text{[HA]}}\right )\\\\0.45& = & \log \left(\dfrac{[\text{A}^{-}]}{\text{[HA]}}\right )\\\\2.82 & = &\dfrac{[\text{A}^{-}]}{\text{[HA]}}\\\\\end{array}\\\text{The base/acid ratio must be $\mathbf{2.82:1}$}

To make the buffer, mix the solutions to get a ratio of 2.82 mol of acetate for every 1 mol of acetic acid.

2. Preparation of pH 9.25 buffer

(a) Choose the conjugate pair

We should choose a buffer with pKₐ close to 9.25.

Bicarbonate has pKₐ = 10.3, so let's make a pH 9.25 bicarbonate buffer.

(b) Protocol for preparation

\begin{array}{rcl}\text{pH} & = & \text{pK}_{\text{a}} + \log \left(\dfrac{[\text{A}^{-}]}{\text{[HA]}}\right )\\\\9.25& = & 10.3 +\log \left(\dfrac{[\text{A}^{-}]}{\text{[HA]}}\right )\\\\-1.05& = & \log \left(\dfrac{[\text{A}^{-}]}{\text{[HA]}}\right )\\\\0.08913& = &\dfrac{[\text{A}^{-}]}{\text{[HA]}}\\\\\dfrac{1}{11.2}& = &\dfrac{[\text{A}^{-}]}{\text{[HA]}}\\\\\end{array}\\\text{The acid/base ratio must be $\mathbf{11.2:1}$}

To make the buffer, mix the solutions to get a ratio of 11.2 mol of bicarbonate for every 1 mol of carbonate.

3 0
3 years ago
What symbol is that plz tell
aleksandr82 [10.1K]
It stands to me it looks like it is a caution
8 0
4 years ago
Read 2 more answers
A prehistoric pharmacist might have been called a
Shkiper50 [21]
A. Shaman

Shaman were revered as people with the ability to communicate with good and evil spirits and heal ailments.
5 0
3 years ago
Adding powdered limestone (calcium carbonate) to a lake affected by acid rain can decrease the availability of phosphate ion, an
Sauron [17]

Answer:

The reaction is:

                                    H⁺

CaCO₃ ⇄ Ca²⁺ + CO₃ ⇄ HCO₃

The standard free energy change is ΔG = ΔH - TΔS

Explanation:

Limestone is a mineral familiar with calcium carbonate, and being very common, the acid present in acid rain dissolves it reacting with carbonate, since the acids present in acid rain are characterized by being highly soluble in water and are also strong acids. The reaction is as follows:

                                    H⁺

CaCO₃ ⇄ Ca²⁺ + CO₃ ⇄ HCO₃

The spontaneity of the reaction is equal to:

ΔG = ΔH - TΔS

The sign of the standard free energy changes from positive to negative.

4 0
4 years ago
H2SO4 + 2NaOH → 2H2O + Na So.
gayaneshka [121]

Answer:

2 mol H

Explanation:

For every 2 mol of NaOH, we're reacting 2 mol of H2O. In order to figure out how many mol of H are needed, it needs to be set up stochiometrically. Starting off with the given value, 1 mol of NaOH, we can then make a mol to mol ratio. For 2 mol of NaOH, we have 2 mol of H2O. For every 2 mol of H2O, we have 4 mol of H (this is because we are multiplying the coefficient by the subscript: 2 × 2). Now, we can solve for our answer.

1 mol NaOH × (2 mol H₂O / 2 mol NaOH) × (4 mol H / 2 mol H₂O)

= 2 mol H

Thus, we get 2 mol of H are needed to completely react 1 mol of NaOH.

7 0
4 years ago
Other questions:
  • Chemistry Help!<br> Reasons why nonmetals form covalent bonds?
    14·2 answers
  • Which description gives the steps for creating hydroelectric power
    9·2 answers
  • 2 different elements have the same number of neutrons​
    8·1 answer
  • What is valence electrons​
    6·1 answer
  • Which of the following statements about FUSION is correct?
    9·2 answers
  • The smallest unit that retains the properties of an element is a(n) _____. atom molecule proton compound neutron
    12·1 answer
  • A catalyst lowers the activation energy for both the forward and the reverse reactions in an equilibrium system, so it has no ef
    5·1 answer
  • Bob uses SI units to measure his running distance. Which units should he use
    12·1 answer
  • The temperature of a 95.4 g piece of copper decreases from 48°C to 25°C when the copper releases - 849 J of heat. What is the sp
    8·1 answer
  • Which of the following is the balanced chemical equation for the combustion of methane, CH4?
    14·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!