Answer:
162 kJ
Explanation:
The reaction given by the problem is:
- NBr₃(g) + 3 H₂O(g) → 3 HOBr(g) + NH₃(g) ∆H = +81 kJ
If we turn it around, we have:
- 3 HOBr(g) + NH₃(g) → NBr₃(g) + 3 H₂O(g) ∆H = -81 kJ
If we think now of HOBr and NH₃ as our reactants, then now we need to find out <u>which one will be the </u><em><u>limiting reactant</u></em> when we have 9 moles of HOBr and 2 moles of NH₃:
- When we have 1 mol NH₃, we need 3 mol HOBr. So when we have 2 moles NH₃, we need 6 moles HOBr. We have more than 6 moles HOBr so that's our <em>reactant in excess</em>, thus NH₃ is our limiting reactant.
-81 kJ is our energy change when there's one mol of NH₃ reacting, so we <u>multiply that value by two when there's two moles of NH₃ reacting</u>. The answer is 81*2 = 162 kJ.
<span>A body that's moving with a negative acceleration is said to be slowing down</span>
The new temperature of the gas is 115 °C
From the question given above, the following data were obtained:
- Initial temperature (T₁) = 25 °C = 25 + 273 = 298 K
- Initial pressure (P₁) = 0.96 atm
- New pressure (P₂) = 1.25 atm
- New temperature (T₂) =?
The new temperature of gas can be obtained as follow:
Therefore, the new temperature is 115 °C
Learn more about gas laws: brainly.com/question/25862018
There are 2 lone pairs
<h3>Further explanation
</h3>
Given
a molecule of calcium sulfide
two valence electron of Calcium(Ca)
six valence electrons of Sulfur(S)
Required
number of lone pairs of electrons
Solution
Lewis structure shows the form of bonds that occur in the valence electrons of an element or compound
Valence electrons are electrons used in a chemical bond
To achieve stability, the element S needs 2 more electrons which are obtained from 2 electrons from the Ca element,
A lone pair electrons means refers to an unshared pair of electrons(not bonding to the other atoms)
An extremely luminous active galactic nucleus