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Marta_Voda [28]

3 years ago

12

Use the periodic table or graphic in lesson. Choose the correct electron configuration of carbon. 1s22s22p1 1s22s22p4 1s22s22p2

1s22s12p2

2 answers:

ycow [4]3 years ago

5 0

1s22s22p2
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alisha [4.7K]3 years ago

4 0

<span>Use the periodic table or graphic in lesson. The correct electron configuration of carbon is 1s22s22p2 </span>

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The equation, 2 H2(g) + O2(g) arrow 2 H2O(l), represents an equation for a standard formation reaction. True False

faust18 [17]

I think it is true. The formation reaction always means that the product substance is made directly and all by the elements of the reactants. And standard means under 25℃ and one atmosphere.

3 0

4 years ago

How have ideas about the atom changed in the last two centureies?

dsp73

In the past a scientist named dalton produced an atomic theory. There were certain problems regarding his views. So, later on scientists like chadwick, rutherford and thompson added some fresh light for the real identification of the atom.
dalton said the atom was the smallest unit and it CANNOT BE DIVIDED ANY FURTHER.
NOTE... this was renected with the discovery of the proton, neutron and electron as the sub atomic particles.

8 0

4 years ago

using the equation above for a nuclear reaction, supply the following answer: there are 96 or 242 or 146 curium neutrons. I need

Sladkaya [172]

Explanation:

Number of Cm neutrons = 242 - 96 = 146

8 0

3 years ago

When two moles of ethane react completely with oxygen, how many moles of carbon dioxide will be produced?A. 2.B. 4.C. 8.D. Unkno

babymother [125]

Answer:

Option B.

Explanation:

As any reaction of combustion, the O₂ is a reactant and the products are CO₂ and H₂O. Combustion reaction for ethane is:

2C₂H₆ + 7O₂ → 4CO₂ + 6H₂O

So 2 moles of ethane react with 7 moles of oxygen to make 4 moles of dioxide and 6 moles of water.

Then 2 moles of ethane will produce 4 moles of CO₂

6 0

3 years ago

A gaseous system undergoes a change in temperature and volume. What is the entropy change for a particle in this system if the f

deff fn [24]

Explanation:

Entropy means the amount of randomness present within the molecules of the body of a substance.

Relation between entropy and microstate is as follows.

S = $K_{b} \times ln \Omega$

where, S = entropy

$K_{b}$ = Boltzmann constant

$\Omega$ = number of microstates

This equation only holds good when the system is neither losing or gaining energy. And, in the given situation we assume that the system is neither gaining or losing energy.

Also, let us assume that $\Omega$ = 1, and $\Omega'$ = 0.833

Therefore, change in entropy will be calculated as follows.

$\Delta S = K_{b} \times ln \Omega' - K_{b} \times ln \Omega$

= $1.38 \times 10^{-23} \times ln(0.833) - 1.38 \times 10^{-23} \times \times ln(1)$

= $1.38 \times 10^{-23} \times (-0.182)$

= $-0.251 \times 10^{-23}$

or, = $-2.51 \times 10^{-24}$

Thus, we can conclude that the entropy change for a particle in the given system is $-2.51 \times 10^{-24}$ J/K particle.

8 0

3 years ago