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Advocard [28]
3 years ago
14

PLZ I NEEEEEEEDDDDDD HELP

Chemistry
2 answers:
Mazyrski [523]3 years ago
4 0

Answer:

Explanation:

1. __1___ Fe + __1___ S → __1___ FeS. 2. __1___ H2 + __1___ Cl2 → __2___ HCl. 3. __2___ Mg + __1___ O2 → __2___ MgO. 4. __1___ O2 + __2___ H2

MrRa [10]3 years ago
3 0

Answer:

2h+02=h20

Explanation:

2 in front of h on left side

2 in front of h on right side

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Which of the following will have the slowest rate of diffusion at a given temperature?
marysya [2.9K]
<h3>Answer:</h3>

Chlorine gas (Cl₂)

<h3>Explanation:</h3>
  • According to the Graham's law of diffusion, the diffusion rate of a gas is inversely proportional to the square root of its density or molar mass.
  • Therefore, a lighter gas will diffuse faster at a given temperature compared to a heavy gas.
  • Consequently, the heavier a gas is then the denser it is and the slower it diffuses at a given temperature and vice versa.

In this case we are given gases, CI₂

, H₂,He and Ne.

  • We are required to identify the gas that will diffuse at the slowest rate.
  • In other words we are required to determine the heaviest gas.

Looking at the molar mass of the gases given;

Cl₂- 70.91 g/mol

H₂- 2.02 g/mol

He - 4.00 g/mol

Ne- 20.18 g/mol

Therefore, chlorine gas is the heaviest and thus will diffuse at the slowest rate among the choices given.

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Check my answers please! 1.Which of the following conditions increases the number of collisions between reactant molecules in a
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<span>I was correct... 1 is adding more reactant molecules and 2 was decreasing in ch3br concentration over time </span>
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frez [133]
Answer:

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If an atom loses a nuetron, what happens to the overall electric charge
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Read 2 more answers
). In a titration, a student obtained an average titre value of 3.9 cm3 of 0.3 M HCl. If the volume of Na2CO3 solution used is 1
Oliga [24]

Answer:

I) 0.0585 M

ii)6.2 g dm-3

Explanation:

The reaction equation is given as;

Na2CO3(aq) +2HCl(aq)------> 2NaCl(aq) + CO2(g) +H2O(l)

Concentration of acid CA= 0.3 M

Volume of acid VA= 3.9 cm^3

Concentration of base CB= the unknown

Volume of base VB= 10 cm^3

Number of moles of acid NA= 2

Number of moles of base NB= 1

From;

CAVA/CBVB= NA/NB

CAVANB=CBVBNA

CB= CAVANB/VBNA

substituting values;

CB= 0.3 × 3.9 × 1/ 10.0 × 2

CB= 0.0585 M

ii) mass concentration= molar concentration × molar mass

Molar mass of Na2CO3= 106 gmol-1

Mass concentration= 0.0585 × 106 = 6.2 g dm-3

5 0
3 years ago
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