The power used by Alex to drag the log across the yard is determined as 2,656 W.
<h3>Mass of the log</h3>
The mass of the log is calculated as follows;
W = mg
m = W/g
m = (400)/9.8
m = 40.82 kg
<h3>Velocity of the log</h3>
K.E = ¹/₂mv²
v² = 2K.E/m
v² = (2 x 900)/(40.82)
v² = 44.096
v = 6.64 m/s
<h3>Power used by Alex</h3>
P = Fv
P = 400 x 6.64
P = 2,656 W
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Given:
Mixture of vitamin water = 75% pure water & 25% concentrated vitamin drink.
To find:
Quantity of water to be added to 16 gallons of concentrated vitamin drink to prepare a tank of vitamin water.
Solution:
Let total amount of mixture be x.
25% of x = 16 gallons (from given information)
When 25% of x is 16 gallons, the remaining 75% of x will be calculated as below:
(16/25)*75 = 48
Answer: 75% of x = 48 gallons. This means 48 gallons pure water is required to be added to mixture to prepare a tank of vitamin water.
Answer:
Explanation:
SODIUM ATOM;
SODIUM ATOM IS NEUTRAL
SODIUM ION;
IT IS A CHARGED SPECIE WITH A CHARGE OF +1
SODIUM ATOM:
THE NUMBER OF PROTONS AND ELECTRONS ARE SAME ie:11
SODIUM ION:
NUMBER OF PROTONS AND ELECTRONS ARE NOT SAME ie. ELETRON: 10, PROTONS:11
HOPE IT WILL HELP:)
<h2>Answer:</h2><h3>Part 1:</h3>
Location the element zinc (Zn) on the periodic table:
- Group number : 12
- Period number : 4
- Block : d block
- Element : Transition elements.
<h3>Part 2:</h3>
Protons in an atom of Zn: 30
<h3>Part 3:</h3>
Electrons in a Zn atom: 30
<h3>Part 4 :</h3>
Neutron in an atom of Zn: 35
<h3 />
40.6 kJ of heat energy had been emitted.
CO(g) + 2H2(g) CH3OH(l)CO volume, V (CO), equals 15 L or 0.015 m3.
Temperature = 85 0C = 85 + 273 = 358 K Pressure = 112 kPa = 112,000 PaPV = nRT n= 112000 0.015 / 8.314 358 n(CO) = 0.56 moles,
according to the ideal gas law.H2 volume is 14.4 L or 0.0144 m3
T = 750C + 273 K = 348 K n(H2) = 99191.84 0.0144 m3 / 8.314 348 K = 0.49 moles of H2 Pressure = 744 torr = 99191.84 Pa
Hydrogen is the limiting reagent, according to the calculation above.CH3OH = H2 = 0.49/2 = 0.245 m-238.6 (-110.5) = -128.1 kJ/mol for H(rxn) = H(f) (CH3OH) - H (rxn)
We must now multiply H(rxn) by the number of moles of methanol.
E = H(rxn) n(CH3OH) = 128.1 0.245 = 40.6 kJ.
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