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Scrat [10]
3 years ago
11

Calculate the force constant (in N/m) of its plunger's spring if you must compress it 0.160 m to drive the 0.0540 kg plunger to

a top speed of 25.0 m/s.
Physics
1 answer:
Leni [432]3 years ago
7 0

Answer:1.318 kN/m

Explanation:

Given

compression x=0.16 m

mass of Plunger m=0.0540 kg

Top speed v_{max}=25 m/s

Conserving Energy

Elastic Potential Energy  of spring stored converted in kinetic energy of Plunger

\frac{1}{2}kx^2=\frac{1}{2}mv^2

k\times (0.16)^2=0.054\times 25^2

k=1318.35 N/m

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A motorcycle accelerated from 10 metre per second to 30 metre per second in 6 seconds. How far did it travel in this time ?
Ber [7]
U=10 m/s
v=30 m/s
t=6 sec

therefore, a=(v-u)/t
                   =(30-10)/6
                   =(10/3) ms^-2

now, displacement=ut+0.5*a*t^2
                              =60+ 0.5*(10/3)*36
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And you can solve it in another way:

v^2=u^2+2as
or, s=(v^2-u^2)/2a
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4 years ago
Which of the following best describes the location of the
marshall27 [118]

Answer:

The mantle exists above the crust of the earth

8 0
3 years ago
In the Bohr model of the hydrogen atom, the speed of the electron is approximately 2.2 106 m/s.
Murrr4er [49]

The central force acting on the electron as it revolves in a circular orbit is 9.52 \times 10^{-8} \ N.

The given parameters;

  • <em>speed of electron, v = 2.2 x 10⁶ m/s</em>
  • <em>radius of the circle, r = 4.63 x 10⁻¹¹ m</em>

<em />

The central force acting on the electron as it revolves in a circular orbit is calculated as follows;

F = \frac{M_e v^2}{r} \\\\

where;

M_e is mass of electron = 9.11 x 10⁻³¹ kg

F = \frac{(9.11 \times 10^{-31}) \times(2.2\times 10^6)^2 }{4.63 \times 10^{-11}} \\\\F = 9.52 \times 10^{-8} \ N

Thus, the central force acting on the electron as it revolves in a circular orbit is 9.52 \times 10^{-8} \ N.

Learn more about centripetal force here:brainly.com/question/20905151

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3 years ago
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