Answer:
P=740 KPa
Δ=7.4 mm
Explanation:
Given that
Diameter of plunger,d=30 mm
Diameter of sleeve ,D=32 mm
Length .L=50 mm
E= 5 MPa
n=0.45
As we know that
Lateral strain



We know that




So the axial pressure


P=740 KPa
The movement in the sleeve


Δ=7.4 mm
Answer:
$25
Explanation:
The computation of the intrinsic value of the stock is shown below:
As we know that
Intrinsic value or Price = Dividend ÷ (Cost of equity - growth rate)
where,
Cost of equity or ke is
= Risk free rate of return + beta × (Market rate of return - risk free rate of return)
= 6% + 0.75 × (14% - 6%)
= 12 %
So the intrinsic value is
= $1.50 ÷ (12% - 6%)
= $25
Lets do
We know
The rate of change of velocity is acceleration .


Integrate both sides

As acceleration is constant .Take it outside of integral .On velocity we can take limit u to v and time from 0 to t

Hence



The symbol "E3" represents the energy of electrons in the third energy level.
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Answer:
The second ball lands 1.5 s after the first ball.
Explanation:
Given;
initial velocity of the ball, u = 12 m/s
height of fall, h = 35 m
initial velocity of the second, v = 12 m/s
Time taken for the first ball to land;

determine the maximum height reached by the second ball;
v² = u² -2gh
at maximum height, the final velocity, v = 0
0 = 12² - (2 x 9.8)h
19.6h = 144
h = 144 / 19.6
h = 7.35 m
time to reach this height;

Total height above the ground to be traveled by the second ball is given as;
= 7.35 m + 35m
= 42.35 m
Time taken for the second ball to fall from this height;

total time spent in air by the second ball;
T = t₁ + t₂
T = 1.23 s + 2.94 s
T = 4.17 s
Time taken for the second ball to land after the first ball is given by;
t = 4.17 s - 2.67 s
T = 1.5 s
Therefore, the second ball lands 1.5 s after the first ball.