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Scrat [10]
3 years ago
11

Calculate the force constant (in N/m) of its plunger's spring if you must compress it 0.160 m to drive the 0.0540 kg plunger to

a top speed of 25.0 m/s.
Physics
1 answer:
Leni [432]3 years ago
7 0

Answer:1.318 kN/m

Explanation:

Given

compression x=0.16 m

mass of Plunger m=0.0540 kg

Top speed v_{max}=25 m/s

Conserving Energy

Elastic Potential Energy  of spring stored converted in kinetic energy of Plunger

\frac{1}{2}kx^2=\frac{1}{2}mv^2

k\times (0.16)^2=0.054\times 25^2

k=1318.35 N/m

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Compare the current in the 8-ohm resistors to the current in the 4-ohm resistors.
Gemiola [76]

Answer:

a)   i₈ = 0.5 i₄,  b)   i₁₀ = 0.3 i₃,    i₁₀ = 0.8 i₈

Explanation:

For this exercise we use ohm's law

       V = i R

        i = V / R

we assume that the applied voltage is the same in all cases

let's find the current for each resistance

         

R = 4 Ω

         i₄ = V / 4

R = 8 Ω

         i₈ = V / 8

we look for the relationship between these two currents

         i₈ /i₄ = 4/8 = ½

         i₈ = 0.5 i₄

R = 3 Ω

        i₃ = V3

R = 10 Ω

         

        i₁₀ = V / 10

   

we look for relationships

       i₁₀ / 1₃ = 3/10

       i₁₀ = 0.3 i₃

       i₁₀ / 1₈ = 8/10

       i₁₀ = 0.8 i₈

7 0
3 years ago
Which of these is a characteristic of the Milky Way galaxy
IRINA_888 [86]

Answer:

A

Explanation:

3 0
3 years ago
1. A sprinter races in the 100 meter dash. It takes him 10 second to reach the finish line
poizon [28]

Answer:

v = 10 m/s

Explanation:

Given that,

Distance covered by a sprinter, d = 100 m

Time taken by him to reach the finish line, t = 10 s

We need to find his average velocity. We know that velocity is equal to the distance covered divided by time taken. So,

v = d/t

v=\dfrac{100\ m}{10\ s}\\\\v=10\ m/s

Hence, his average velocity is 10 m/s.

6 0
3 years ago
Which is more dense lead or Gold ?
WARRIOR [948]

Answer:

Gold is more dense.

Gold sinks faster than lead. That's why gold is found in the bottom of a gold pan or river.

8 0
3 years ago
Read 2 more answers
what is the resistance of a car light bulb that conducts 0.025A current when connected to a 12V car accumulator? is the current
Sophie [7]

One form of Ohm's Law says . . . . . Resistance = Voltage / Current .

R = V / I

R = (12 v) / (0.025 A)

R = (12 / 0.025) (V/I)

<em>R = 480 Ohms</em>

I don't know if the current in the bulb is steady, because I don't know what a car's "accumulator" is.  (Floogle isn't sure either.)

If you're referring to the car's battery, then the current is quite steady, because the battery is a purely DC storage container.

If you're referring to the car's "alternator" ... the thing that generates electrical energy in a car to keep the battery charged ... then the current is pulsating DC, because that's the form of the alternator's output.  

7 0
3 years ago
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