Answer:
The percent yield of a reaction is 48.05%.
Explanation:

Volume of water obtained from the reaction , V= 5.76 mL
Mass of water = m = Experimental yield of water
Density of water = d = 1.00 g/mL

Theoretical yield of water : T
Moles of tungsten(VI) oxide = 
According to recation 1 mole of tungsten(VI) oxide gives 3 moles of water, then 0.2220 moles of tungsten(VI) oxide will give:

Mass of 0.6660 moles of water:
0.666 mol × 18 g/mol = 11.988 g
Theoretical yield of water : T = 11.988 g
To calculate the percentage yield of reaction , we use the equation:


The percent yield of a reaction is 48.05%.
Answer:
Sodium Hydroxide + Sulfuric Acid = Sodium Sulfate + Water
2NaOH + H2SO4 → Na2SO4 + 2H2O
Explanation:
To balance a chemical equation, enter an equation of a chemical reaction and press the Balance button. The balanced equation will appear above.
Use uppercase for the first character in the element and lowercase for the second character. Examples: Fe, Au, Co, Br, C, O, N, F.
Ionic charges are not yet supported and will be ignored.
Replace immutable groups in compounds to avoid ambiguity. For example, C6H5C2H5 + O2 = C6H5OH + CO2 + H2O will not be balanced, but XC2H5 + O2 = XOH + CO2 + H2O will.
Compound states [like (s) (aq) or (g)] are not required.
You can use parenthesis () or brackets [].
First, we apply the law of conservation of mass which states that the total mass in a system remains constant.
Therefore, there must be 5.00 g of sulfur and 4.99 g of oxygen in the product. Now, we determine the mass percentage using:
Mass % = (mass of sulfur x 100) / total mass of compound
Mass % = (5 * 100) / (5 + 4.99)
Mass % = 50.05%
The product contains 50.05% sulfur by mass.
<span>You use the Henderson - Hasselbalch equation
pH = pKa + log ([salt]/[acid])
pKa = -log (8.2*10^-5) = 4.081
pH = 4.081 + (0.590/0.190)
pH = 4.081 + log 3.105
pH = 4.081 + 0.49206
pH = 4.573</span>
Correct option:
The correct name for
is diphosphorus pentoxide.
Why
is called diphosphorus pentoxide?
is commonly known as diphosphorus pentoxide.
Phosphorus pentoxide has an intriguing property in that
is actually its empirical formula, whereas
is its actual molecular formula.
However, the name of the chemical was obtained from its empirical formula rather than from its molecular formula. The official name for this substance is diphosphorus pentoxide.
Oxygen-containing binary compounds have "oxide" as their "last name." Phosphorus is the "first name."
We list each atom's numbers below:
The di- and Penta- prefixes are used to indicate the presence of two and five oxygen atoms, respectively, in the molecule.
Learn more about diphosphorus pentoxide here,
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