A fairly low melting point<span>, </span>and<span> cannot...electricity regardless </span>of<span> state. Another important </span>difference between the<span> two </span>is<span> that an </span>ionic compound is<span> a crystalline...</span>
Answer:
They become ductile and deform plastically
Explanation:
When rocks are buried by the materials up to a greater depth, then the confining pressure increases significantly. This results in the ductile behavior of the rocks at such depth. These rocks are present in the ductile region where the depth is about more than 20 to 30 km. Here the rocks are subjected to extremely high pressure and temperature conditions, which favors the transformation of rocks into more higher-grade metamorphic rocks. It is also enhanced due to the geothermal gradient.
Under such high pressure and temperature, the rocks show the behavior of plasticity, where the rocks undergo bending, buckling as well as they tend to flow, and there occurs low strain rate, resulting in the permanent deformation of rocks.
Thus, the rocks become ductile and deform plastically at such conditions.
Answer:
The answer is
<h2>2 cm/year</h2>
Explanation:
To find the rate in cm/year we must first convert 200 m into cm
1 m = 100 cm
if 1 m = 100 cm
Then 200 m = 200 × 100 = 20 ,000 cm
So the rate is
<h2>
</h2>
<u>Reduce the fraction with 10,000</u>
We have the final answer as
<h3>2 cm/year</h3>
Hope this helps you
The equilibrium constant could be found using the relationship Kaq = [H^+] [HCOO-]/HCOOH
<h3>What is the equilibrium constant?</h3>
The equilibrium constant is a value that shows us the extent to which reactants are converted into products. We know that a very high value of the equilibrium constant implies that the reactants are mostly converted into products.
Now we have the equation of the reaction as; HCOOH(aq)⇌H^+(aq) + 〖HCOO〗^- (aq). The equilibrium constant ca now be written in terms of Kaq.
Thus the equilibrium constant is;
Kaq = [H^+] [HCOO-]/HCOOH
Learn more about equilibrium constant:brainly.com/question/10038290
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Combination
Hope this helps :)
