You're going to use the constant acceleration motion equation for velocity and displacement:
(V)final²=(V)initial²+2a(Δx)
Given:
a=0.500m/s²
Δx=4.75m
(V)intial=0m
(V)final= UNKNOWN
(V)final= 2.179m/s
Answer:
a = 5.05 x 10¹⁴ m/s²
Explanation:
Consider the motion along the horizontal direction
= velocity along the horizontal direction = 3.0 x 10⁶ m/s
t = time of travel
X = horizontal distance traveled = 11 cm = 0.11 m
Time of travel can be given as
inserting the values
t = 0.11/(3.0 x 10⁶)
t = 3.67 x 10⁻⁸ sec
Consider the motion along the vertical direction
Y = vertical distance traveled = 34 cm = 0.34 m
a = acceleration = ?
t = time of travel = 3.67 x 10⁻⁸ sec
= initial velocity along the vertical direction = 0 m/s
Using the kinematics equation
Y = t + (0.5) a t²
0.34 = (0) (3.67 x 10⁻⁸) + (0.5) a (3.67 x 10⁻⁸)²
a = 5.05 x 10¹⁴ m/s²
Answer:
1 m
Explanation:
Given
The mirror is a concave mirror.
Radius of curvature = 2 m
Now, for a parallel beam after reflection occurs, the object should be placed at the focus of the mirror.
We know, focal length = radius of curvature / 2
= 2 / 2
= 1
Thus the focal length is 1 m.
Hence the object should be placed at 1 m from the concave mirror for parallel beam reflection.
Answer:
"the" (and any subsequent words) was ignored because we limit queries to 32 words
Answer:
The Admins ans such of brainly probably thought the answer was either inappropriate or wrong
Explanation:
