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Komok [63]
3 years ago
7

Light could be thought of as a stream of tiny particles discharged by _______ objects that travel in straight paths. *

Physics
1 answer:
Gelneren [198K]3 years ago
5 0

Answer: Light could be thought of as a stream of tiny particles discharged by luminous objects that travel in straight paths.

Explanation:

We can define "radiation" as the transmision of energy trough waves or particles.

Particularly, light is a form of electromagnetic radiation, so the "tiny particles" of light are discharged by a radiating object, particularly we can be more explicit and call it a luminous object, in this way we are being specific about the nature of the radiation of the object.

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Radiation emitted by a body is a consequence of thermal agitation of its composing molecules. so...<span> electromagnetic waves ?</span>
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3 years ago
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A spring gun is made by compressing a spring in a tube and then latching the spring at the compressed position. A 4.87-g pellet
Serga [27]

Complete Question

The complete question is shown on the first uploaded image

Answer:

The work done by the spring is = 0.27 J

Explanation:

Force = torque × length

Given

F = 9.13 N

length (L) = 5.91 cm  = 0.0591 m                         [Note 1 m = 100 cm ]

considering the formula above

          9.13 = k * 0.0591    where k denotes torque

          k = 154.48\ N/m

Energy Stored  = \frac{1}{2} k x^2

                          = \frac{1}{2} * 154.48 * (0.0591)^2

                         = 0.27J  

8 0
3 years ago
Magnesium hydroxide is a common ___?
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Answer:

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Explanation:

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3 years ago
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A light horizontal spring has a spring constant of 138 N/m. A 3.35 kg block is pressed against one end of the spring, compressin
BARSIC [14]

Answer:

U_k = 0.113

Explanation:

using the law of the conservation of energy:

E_i -E_f=W_f

\frac{1}{2}Kx^2=NU_kd

where K is the spring constant, x is the spring compression, N is the normal force of the block, U_k is the coefficiet of kinetic friction and d is the distance.

Also, by laws of newton, N is calculated by:

N = mg

N = 3.35 kg * 9.81 m/s

N = 32.8635

So, Replacing values on the first equation, we get:

\frac{1}{2}(138)(0.123)^2= (32.8635)U_k(0.281m)

solving for U_k:

U_k = 0.113

8 0
3 years ago
Question is attatched!
lina2011 [118]
All it does is lets him pull in a more convenient direction to raise the load. It has no effect on the required force.
4 0
3 years ago
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