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Komok [63]
3 years ago
7

Light could be thought of as a stream of tiny particles discharged by _______ objects that travel in straight paths. *

Physics
1 answer:
Gelneren [198K]3 years ago
5 0

Answer: Light could be thought of as a stream of tiny particles discharged by luminous objects that travel in straight paths.

Explanation:

We can define "radiation" as the transmision of energy trough waves or particles.

Particularly, light is a form of electromagnetic radiation, so the "tiny particles" of light are discharged by a radiating object, particularly we can be more explicit and call it a luminous object, in this way we are being specific about the nature of the radiation of the object.

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Water towers store water above the level of consumers for times of heavy use, eliminating the need for high-speed pumps. How hig
Salsk061 [2.6K]

Answer:

So height will be 47.387 m

Explanation:

We have given gauge pressure P=4.63\times 10^5N/m^2

Density of water \rho =997kg/m^3

Acceleration due to gravity g=9.8m/sec^2

We know that pressure is given as P=\rho gh

4.63\times 10^5=997\times 9.8\times h

h=47.387m

So height will be 47.387 m

4 0
3 years ago
Two projectiles are fired at equal speeds but different angles. One is fired at angle of 30 degrees and the other at 60 degrees.
Doss [256]

Answer:

14 degrees

Explanation:

because you can divide all and find the angle to find the answer

hope it's help ty make me brainless pls

3 0
2 years ago
Three point charges are positioned on the x axis. If the charges and corresponding positions are +32 µC at x = 0, +20 µC at x =
Troyanec [42]

Answer:

The magnitude of the electrostatic force on \mathrm{+32\,\mu C} is:   \mathbf{12\;N}

Explanation:

Consider

  • q_1=+32\;\mu\text{C} is at position x_1=0\;\text{m}
  • q_2=+20\;\mu\text{C} is at position x_2=40\;\text{cm}
  • q_3=-60\;\mu\text{C} is at position x_3=60\;\text{cm}

The sum of all horizontal forces on q_1 is given as

  \sum F_x=F_{12}+F_{13}

where

  • F_{12} is the force exerted by q_2
  • F_{13} is the force exerted by q_3

The force on q_1 exerted by q_2 is repulsive, so the direction of the force F_{12} is to the left (negative direction). Thus

  F_{12}=-\frac{K\,|q_1|\,|q_2|}{r_{12}^2}\\F_{12}=-\frac{K\,|q_1|\,|q_2|}{(x_2\;-\;x_1)^2}\\F_{12}=\mathrm{-\frac{(8.988\times10^9\;\frac{Nm^2}{C^2})\,|+32\;\mu C|\,|+20\;\mu C|}{(40\;cm\;-\;0\;cm)^2}}\\F_{12}=\mathrm{-\frac{(8.988\times10^9\;\frac{Nm^2}{C^2})\,(32\;\mu C)\,(20\;\mu C)}{(40\;cm)^2}}\\F_{12}=\mathrm{-\frac{(8.988\times10^9\;\frac{Nm^2}{C^2})\,(32\times10^{-6}\;C)\,(20\times10^{-6}\;C)}{(0.40\;m)^2}}\\F_{12}=\mathrm{-36\;N}

The force on q_1 exerted by q_3 is attractive, so the direction of the force F_{13} is to the right (positive direction). Thus

  F_{13}=+\frac{K\,|q_1|\,|q_3|}{r_{13}^2}\\F_{13}=+\frac{K\,|q_1|\,|q_3|}{(x_3\;-\;x_1)^2}\\F_{13}=\mathrm{+\frac{(9\times10^9\;\frac{Nm^2}{C^2})\,|+32\;\mu C|\,|-60\;\mu C|}{(60\;cm\;-\;0\;cm)^2}}\\F_{13}=\mathrm{+\frac{(9\times10^9\;\frac{Nm^2}{C^2})\,(32\;\mu C)\,(60\;\mu C)}{(60\;cm)^2}}\\F_{13}=\mathrm{+\frac{(9\times10^9\;\frac{Nm^2}{C^2})\,(32\times10^{-6}\;C)\,(60\times10^{-6}\;C)}{(0.60\;m)^2}}\\F_{13}=\mathrm{+48\;N}

Therefore

  \sum F_x=\mathrm{-36\;N+48\;N} \;\;\;\;\;\Rightarrow\;\;\;\;\; \mathbf{\sum F_x=+12\;N}

the electrostatic force on q_1 is to the right and has a magnitude of \mathbf{12\;N}

8 0
3 years ago
Thomas Newcomen was the first to produce a working steam engine. Why is the work of James Watt more widely known than the work o
LenaWriter [7]

Answer:

The steam engine of James watt is more efficient than Newcomen ans more suitable for the industrial revolution.

Explanation:

James Watt is more widely know for working steam engine because Watt has created better engine which is suitable for the industrial revolution. The steam engine of James watt is more efficient than Newcomen. Watt developed the condensing arrangement by using piston which lessen the initial pressure leading to effectively worked than Newcomen's

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3 years ago
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