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serg [7]
3 years ago
5

A team of scientists have identifyed a group of fish in the San Franscisco Bay that have never been seen in this location before

. These fish are commonly found in the waters off of Japan. We would call these fish
A. native species
B. evolved species
C. intruding species
D. invasive species
Chemistry
2 answers:
sergejj [24]3 years ago
8 0
The reason why is because mabye they got trapped or something in san francisco, and since they couldnt go back to japan, they had to evolve into san francisco in order to stay alive
marshall27 [118]3 years ago
6 0
Evolved. the reason why is because mabye they got trapped or something in san francisco, and since they couldnt go back to japan, they had to evolve into san francisco in order to stay alive

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How many moles are in 337 grams of tellurium?
MaRussiya [10]

about 43001 is it i think

3 0
3 years ago
How many grams of sodium carbonate are produced when 5.3 moles of sodium phosphate reacts with aluminum carbonate?
Korvikt [17]

Answer: There is 842.54 grams of sodium carbonate are produced when 5.3 moles of sodium phosphate reacts with aluminum carbonate.

Explanation:

Chemical equation depicting reaction between sodium phosphate and aluminum carbonate is as follows.

Al_{2}(CO_{3})_{3} + 2Na_{3}PO_{4} \rightarrow 2AlPO_{4} + 3Na_{2}CO_{3}

As this equation contains same number of atoms on both reactant and product side. So, this equation is a balanced equation.

According to the equation, 2 moles of sodium phosphate is giving 3 moles of sodium carbonate.

Therefore, sodium carbonate formed by 5.3 moles of sodium phosphate is as follows.

\frac{3}{2} \times 5.3 mol\\= 7.95 mol

As number of moles is the mass of substance divided by its molar mass. So, mass of sodium carbonate ( molar mass = 105.98 g/mol) is as follows.

No. of moles = \frac{mass}{molar mass}\\7.95 mol = \frac{mass}{105.98 g/mol}\\mass = 842.54 g

Thus, we can conclude that there is 842.54 grams of sodium carbonate are produced when 5.3 moles of sodium phosphate reacts with aluminum carbonate.

8 0
2 years ago
If iodine-131 has a half-life of 8 days, how much of a 64.0 g sample of iodine-131 will remain after 32 day?
Mariulka [41]

Answer:

4 g OF IODINE-131 WILL REMAIN AFTER 32 DAYS.

Explanation:

Half life (t1/2) = 8 days

Original mass (No) = 64 g

Elapsed time (t) = 32 days

Mass remaining (Nt) = ?

Using the half life equation we can obtain the mass remaining (Nt)

Nt = No (1/2) ^t/t1/2

Substituting the values, we have;

Nt = 64 * ( 1/2 ) ^32/8

Nt = 64 * (1/2) ^4

Nt = 64 * 0.0625

Nt = 4 g

So therefore, 4 g of the iodine-131 sample will remain after 32 days with its half life of 8 days.

8 0
3 years ago
What would the total mass of a 4.9 mole sample of Barium (Ba) be if its Molar Mass is 137g?
Aleksandr-060686 [28]

Answer:

m = 671 grams

Explanation:

Given that,

No of moles, n = 4.9

Molar mass of Barium, M = 137 g

Mass divided by molar mass is equal to no of moles. It can be given by the formula as follows :

n=\dfrac{m}{M}\\\\m=n\times M\\\\m=4.9\times 137\\\\m=671.3\ g

or

m = 671 grams

So, the total mass of the sample of Barium is 671 grams.

8 0
2 years ago
Um exemplo de força elétrica.
evablogger [386]

Answer:

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7 0
2 years ago
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