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ryzh [129]
3 years ago
9

The mole concept is important in chemistry because 1. it allows us to distinguish between elements and compounds. 2. it provides

a universally accepted standard for mass. 3. atoms and molecules are very small and the mole concept allows us to count atoms and molecules by weighing macroscopic amounts of material. 4. it explains the properties of gases. 5. it establishes a standard for reaction stoichiometry. 0
Chemistry
1 answer:
Rufina [12.5K]3 years ago
6 0
Answer:
             <span>The mole concept is important in chemistry because, "</span>Atoms and molecules are very small and the mole concept allows us to count atoms and molecules by weighing macroscopic amounts of material".

Explanation:
                   To understand this question lets take an example of Hydrogen atom. Let suppose you need to react Hydrogen with Oxygen. You need exactly Two Hydrogen atoms and one Oxygen atom to form one water molecule.
                  The mass of 1 hydrogen atom is 1.76 × 10⁻²⁴ grams. How will you count the Hydrogen atoms??? How can you measure exactly for 1 Million Hydrogen Atoms???
                   Answer to these questions and Calculations lies in Mole. It is found that 1 Mole of Hydrogen weights exactly 1.008 gram and contains 6.022 × 10²³ atoms. Now, having this reference in hand you can calculate for any number of Hydrogen atoms.

Result:
           So the Mole helps us to zoom a microscopic level to a macroscopic level. :)
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Someone please help! this is the last question<br>I only need help with B.<br><br>​
ludmilkaskok [199]

1. mol ratio of Al(NO₃)₃ : Na₂CO₃ = 2 : 3

2. Na₂CO₃ as a limiting reactant

<h3>Further explanation</h3>

Given

Reaction

2 Al(NO₃)₃ + 3 Na₂CO₃ → Al₂(CO₃)₃ + 6 NaNO₃

Required

mol ratio

Limiting reactant

Solution

The reaction coefficient in the chemical equation shows the mole ratio of the components of the compound involved in the reaction (reactants and products)

1. From the equation mol ratio of Al(NO₃)₃ : Na₂CO₃ = 2 : 3

2. mol : coefficient of Al(NO₃)₃ : Na₂CO₃ = 2 mole/2 : 2 mole/3 = 1 : 0.67

Na₂CO₃ as a limiting reactant (smaller)

6 0
3 years ago
Match each term to its description. Match Term Definition Excess reactant A) Reactant that can produce more of the product Limit
faust18 [17]

Answer:

Explanation:

A) Reactant that can produce more of the product

Excess reactant:

In a given reaction, the reactant that is in excess supply is the excess reactant. If the amount of the excess reactant is match, more of the product will be produced.

B) Reactant that can produce a lesser amount of the product

Limiting reactant

The limiting reactant restricts the progress of the reaction. It determines the amount of product that can be formed.

C) Amount of product predicted to be produced by the given reactants

Theoretical yield

For a given amount of reactants, the theoretical yield determines the amount of products that can be produced.

5 0
3 years ago
Can you add more points to question pls
Zarrin [17]

what do you mean? explain what you r trying to dsay


3 0
3 years ago
What is the volume of 18.9 g of a liquid that has a density of 0.956 g/ml
Alex_Xolod [135]
The volume is 19.76987448 by taking the known variables mass=18.9g and density=0.956g/ml
To get volume you divide the mass by the density which gives you about
19.77 ml in volume
6 0
3 years ago
A sample of gas occupies 7.80 liters at 425=C2=B0C? What will be the volume= of the gas at 35=C2=B0C if the pressure does not ch
luda_lava [24]

To solve this we assume that the gas inside the balloon is an ideal gas. Then, we can use the ideal gas equation which is expressed as PV = nRT. At a constant pressure and number of moles of the gas the ratio T/V is equal to some constant. At another set of condition of temperature, the constant is still the same. Calculations are as follows:

T1 / V1 = T2 / V2

V2 = T2 x V1 / T1

V2 = 308.15 x 7.80 / 698.15

V2 =3.44 L


7 0
3 years ago
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