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RSB [31]
4 years ago
5

What is the power dissipated by the parallel resistor circuit shown above?

Physics
1 answer:
MatroZZZ [7]4 years ago
3 0
One formula for power is

P = (voltage squared)/(resistance).

Resistance of 3 equal resistors in parallel is 1/3 of the value = 100/3 ohms.

Power = (40^2)/ (100/3)

. = (1600 • 3) / (100)

. =. 48 watts .
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6 0
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Read 2 more answers
A negative charge of -6.0x10-6 C exerts an
Ray Of Light [21]

The magnitude of the second charge given that the first is –6×10¯⁶ C and is located 0.05 m away is +3.0×10¯⁶ C

<h3>Coulomb's law equation </h3>

F = Kq₁q₂ / r²

Where

  • F is the force of attraction
  • K is the electrical constant
  • q₁ and q₂ are two point charges
  • r is the distance apart

<h3>How to determine the second charge </h3>
  • Charge 1 (q₁) = –6×10¯⁶ C
  • Electric constant (K) = 9×10⁹ Nm²/C²
  • Distance apart (r) = 0.05 m
  • Force (F) = 65 N
  • Charge 2 (q₂) =?

F = Kq₁q₂ / r²

Cross multiply

Fr² = Kq₁q₂

Divide both side by Kq₁

q₂ = Fr² / Kq₁

q₂ = (65 × 0.05²) / (9×10⁹ × 6×10¯⁶)

q₂ = +3.0×10¯⁶ C (since the force is attractive)

Learn more about Coulomb's law:

brainly.com/question/506926

7 0
2 years ago
Need help with number 1
Margarita [4]
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3 0
3 years ago
A ball Of Mass. 0.5 kg initially at rest is kick directly toward offense from appoint 20 m away as shown below the velocity of t
snow_tiger [21]

Answer:

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Explanation:

8 0
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