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3 years ago

What is the power dissipated by the parallel resistor circuit shown above?

Physics

1 answer:

MatroZZZ [7]3 years ago

3 0

One formula for power is

P = (voltage squared)/(resistance).

Resistance of 3 equal resistors in parallel is 1/3 of the value = 100/3 ohms.

Power = (40^2)/ (100/3)

. = (1600 • 3) / (100)

. =. 48 watts .

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$P.E = K.E\\\\mgh = \frac{1}{2} mv^2\\\\h = \frac{v^2}{2g} \\\\h = \frac{0.8^2}{2\times 10} \\\\h = 0.032 \ m$

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