Displacement of a body is always in a straight line in the direction of the final position regardless of the path taken to reach the final position.
Therefore, the displacement of the car can be obtained by joining the car's initial position to the final position and then counting the number of squares covered by the line. Then we multiply the number of squares by the scale and note the direction of the final position from the initial.
that is: 4×1km= 4km North since displacement is a vector.
You should have the velocity as a function of time either given explicitly or implicitly (a graph)
v = ds/dt (differentiating the position vector)
integrating the acceleration.
you can use impulse or work and energy principle and also newton law of motion to find acceleration then velocity
NOT SURE IF THAT WHAT YOU WANT.
Answer:
322.6 m/s
Explanation:
Given that there are two components of position;
x= vot
y component is;
y= 1.9 - gt^2/2
When the bullet hits the ground, y=0
1.9 -gt^2/2 =0
Where g = 10ms^-2
t= √2 × 1.9/10
t= 0.62 secs
Therefore,
x= vot
vo = x/t
Where, x= 200 m
vo= 200/0.62 =
vo= 322.6 m/s