Well we know it has to be greater than 300,000 km/s since we can't see it.
We can't calculate it any closer than that using the given information.
- Let, the maximum height covered by projectile be


- Projectile is thrown with a velocity = v
- Angle of projection = θ
- Velocity of projectile at a height half of the maximum height covered be

______________________________
Then –










- Now, the vertical component of velocity of projectile at the height half of
will be –


Therefore, the vertical component of velocity of projectile at this height will be–
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Explanation:
w = (4.52 ± 0.02) cm, x = ( 2.0 ± 0.2) cm, y = (3.0 ± 0.6) cm. Find z = x + y - w and its uncertainty.
z = x + y - w = 2.0 + 3.0 - 4.5 = 0.5 cm
Dz = Dx + Dy + Dw = 0.2 + 0.6 + 0.02 = 0.82 rounding to 0.8 cm
So z = (0.5 ± 0.8) cm
Solution with standard deviations, Eq. 1b, Dz = 0.633 cm
z = (0.5 ± 0.6) cm
Notice that we round the uncertainty to one significant figure and round the answer to match.
Answer:
person is accelerating downwards
Explanation:
We are told that the force of the person standing on the elevator is 800 N acting downwards.
We are also told that the upward force of the elevator on the person is 600 Newtons.
This means that Upward force is lesser than downward force and thus the person is accelerating downwards
In trajectory, acceleration vector is not the same with the velocity vector but it depends on the change in velocity. The acceleration path is perpendicular to the velocity vector path. The Correct answers are:
a.) D
b.) B
c.) C
d.) A
A Vector is a quantity that has both magnitude and direction.
Given that a ball is fired from a cannon at point 1 and follows the trajectory shown in the figure.
a.) The vector best represents the ball's velocity at position 2 is D
b.) The vector best represents the ball's acceleration at point 2 is B
c.) Which vector best represents the ball's velocity at position 3 = C
d.) Which vector best represents the ball's acceleration at point = A
In trajectory, acceleration vector is not the same with the velocity vector but depends on the change in velocity. The acceleration path is perpendicular to the velocity vector path.
At point 3, since the ball path is parabolic, the velocity at that point is not equal to zero but will tend to take a horizontal path.
Learn more here: brainly.com/question/25519989