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3 years ago

A mineral is made from what in the ground

1 answer:

3 0

Minerals are solid substances that occur naturally. They can be made from a single element (like gold or copper) or from a combination of elements.

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The molecular mass of the compound is 132 amu What is molecular formula?

vlada-n [284]

I am assuming that this compound contains carbon, hydrogen and oxygen. The molar mass of carbon, hydrogen and oxygen is 12, 1 and 16 grams/mol. Given these molar mass we now need to know the number of C H and O in the compound. To have 132 the compound must be C6H12O3

3 0

3 years ago

Give three examples,from the lab where potential energy was converted to kinetic energy?

creativ13 [48]

Answer:

*a car geared neutral that is at a stop. two men start pushing it

*tire physical therapy. trie is at rest until you come up to the tire and flip it

*pushing a wheel barrel

Explanation:

everthing has to be at a complete stop then through energy be moved

7 0

3 years ago

Help with atoms WILL MARK BRAINLIEST

Eddi Din [679]

Answer:

C 1:1

Explanation:

Hydrogen loses an electron to becone +1 which is a cation and flourine gains that electron to have a full outer shell on the 2p subshell to become -1 and is an anion so the ratio is 1:1.

4 0

2 years ago

A gaseous mixture composed of 20% CH4, 30% C2H4, 35% C2H2, and 15% C2H20. What is the average molecular weight of the mixture? a

Semenov [28]

Answer: The correct answer is Option d.

Explanation:

We are given:

Mass percentage of $CH_4$ = 20 %

So, mole fraction of $CH_4$ = 0.2

Mass percentage of $C_2H_4$ = 30 %

So, mole fraction of $C_2H_4$ = 0.3

Mass percentage of $C_2H_2$ = 35 %

So, mole fraction of $C_2H_2$ = 0.35

Mass percentage of $C_2H_2O$ = 15 %

So, mole fraction of $C_2H_2O$ = 0.15

We know that:

Molar mass of $CH_4$ = 16 g/mol

Molar mass of $C_2H_4$ = 28 g/mol

Molar mass of $C_2H_2$ = 26 g/mol

Molar mass of $C_2H_2O$ = 48 g/mol

To calculate the average molecular mass of the mixture, we use the equation:

$\text{Average molecular weight of mixture}=\frac{_{i=1}^n\sum{\chi_im_i}}{n_i}$

where,

$\chi_i$ = mole fractions of i-th species

$m_i$ = molar masses of i-th species

$n_i$ = number of observations

Putting values in above equation:

$\text{Average molecular weight}=\frac{(\chi_{CH_4}\times M_{CH_4})+(\chi_{C_2H_4}\times M_{C_2H_4})+(\chi_{C_2H_2}\times M_{C_2H_2})+(\chi_{C_2H_2O}\times M_{C_2H_2O})}{4}$

$\text{Average molecular weight of mixture}=\frac{(0.20\times 16)+(0.30\times 28)+(0.35\times 26)+(0.15\times 42)}{4}\\\\\text{Average molecular weight of mixture}=6.75$

Hence, the correct answer is Option d.

3 0

3 years ago

what is the inferred pressure, in million of atmospheres, in Earth's interior at a depth of 2900 kilometers?

NemiM [27]

Answer:

1.4 millions atmospheres

Explanation:

8 0

3 years ago