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pentagon [3]
3 years ago
9

Two moles of an ideal monatomic gas go through the cycle abc. For the complete cycle, 800 J of heat flows out of the gas. Proces

s ab is at constant pressure, and process bc is at constant volume. States a and b have temperatures Ta = 200 K and Tb = 300 K.
(a) Sketch the all possible pV-diagrarns for the cycle.
(b) What is the work W for the process ca?
Physics
1 answer:
KiRa [710]3 years ago
3 0

a) Sketches of all possible pv-diagrams for the cycle are attached below

b) The work W_{ac} for the process Ca is : 2462.8  J

<u>Given data :</u>

Amount of heat flowing out = 800 J

Ta = 200 K

Tb = 300 K

R = 800

<u>B) Determine the </u><u>work W </u><u>for the process</u><u> Ca</u><u> </u>

Wₐs = -pdv

       = - [ pVb - pVa ] ---- ( 1 )

note : pVb = nRTb ,  pVa = nRTa

Equation ( 1 ) becomes

= -nR [ Tb - Ta ]

= - 2(8.314 ) [ 300 - 200 ]

= - 1662.87

given that W_{bs} = 0 which is isochonic

dv = 0 ( cyclic process ) = d∅ - dw

∴ 0 = 800 - ( Wₐs  +  W_{ac} )

Therefore : W_{ac} = 800 + 1662.8 = 2462.8  J

Hence we can conclude that the work W for the process Ca = 2462.8  J

Learn more about Pv diagrams : brainly.com/question/25401637

Download pdf
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