D? maybe i’m trying to. see if it’s d or b
Answer:
R=V/I=6/2=3ohm
time =5minutes =5*60=300seconds
I=2A
Heat =I^2Rt=(2)^2*3*300=4*900=3600J
The correct answer is:-
alternating.
Answer:
Time of flight A is greatest
Explanation:
Let u₁ , u₂, u₃ be their initial velocity and θ₁ , θ₂ and θ₃ be their angle of projection. They all achieve a common highest height of H.
So
H = u₁² sin²θ₁ /2g
H = u₂² sin²θ₂ /2g
H = u₃² sin²θ₃ /2g
On the basis of these equation we can write
u₁ sinθ₁ =u₂ sinθ₂=u₃ sinθ₃
For maximum range we can write
D = u₁² sin2θ₁ /g
1.5 D = u₂² sin2θ₂ / g
2 D =u₃² sin2θ₃ / g
1.5 D / D = u₂² sin2θ₂ /u₁² sin2θ₁
1.5 = u₂ cosθ₂ /u₁ cosθ₁ ( since , u₁ sinθ₁ =u₂ sinθ₂ )
u₂ cosθ₂ >u₁ cosθ₁
u₂ sinθ₂ < u₁ sinθ₁
2u₂ sinθ₂ / g < 2u₁ sinθ₁ /g
Time of flight B < Time of flight A
Similarly we can prove
Time of flight C < Time of flight B
Hence Time of flight A is greatest .
Answer:
A.) 3605.6 N
B.) 33.7 degree
Explanation:
To find the result force acting on the wing of the airplane, we need to resolve the forces into x and y components
Resolving into x component :
Sum of forces = 3500 - 500 = 3000N
Resolving into y component:
Sum of forces = 2000N
Resultant force Fr = sqrt ( Fx^2 + Fy^2)
Fr = sqrt ( 3000^2 + 2000^2 )
Fr = sqrt ( 9000000 + 4000000 )
Fr = sqrt ( 13000000)
Fr = 3605.6 N
Therefore, resultant force acting on the wing is 3605.6 N
The direction of the vector will be:
Tan Ø = Fy / Fx
Substitute Fx and Fy into the formula
Tan Ø = 2000 / 3000
Tan Ø = 0.66666
Ø = tan^-1(0. 66666)
Ø = 33.7 degree.
