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Rzqust [24]
3 years ago
11

Explain the difference in appearance between a pure substance and a mixture

Chemistry
1 answer:
frosja888 [35]3 years ago
6 0
1) Mix can be divided on components using physical methods like filtration, of evaporation, or distillation and so on. But substance cannot.
2) Substance contains only one kind of the molecules (particles) , but mix can contain several kinds of molecules.
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An atom that has lost one or more electrons is a(n) _______
kompoz [17]

Answer:

An atom that loses one or more valence electrons to become a positively charged ion is known as a cation, while an atom that gains electrons and becomes negatively charged is known as an anion.

8 0
3 years ago
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Calculate the MASS if the density is 2.34 g/mL and the volume is 12.50 mL.
AlexFokin [52]

Answer:

<h2>mass = 29.25 g</h2>

Explanation:

The denisty of a substance can be found by using the formula

Density =  \frac{mass}{volume}

Making mass the subject we have

<h3>mass = Density × volume</h3>

From the question

Density = 2.34 g/mL

volume = 12.50 mL

Substitute the values into the above formula and solve for the mass

That's

mass = 2.34 × 12.50

We have the final answer as

<h3>mass = 29.25 g</h3>

Hope this helps you

3 0
3 years ago
Which one is you fav one
serious [3.7K]

Answer:

the 3rd one

Explanation:

8 0
2 years ago
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What is the chemical reaction that occurs during photosynthesis ​
vfiekz [6]

Answer:

endothermic change occurs

Explanation:

photosynthesis, is an endothermic reaction in which energy is absorbed from the surrounding.

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2 years ago
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Part 1: What is the final volume in milliliters when 0.730 L of a 44.8 % (m/v) solution is diluted to 23.3 % (m/v)?
Andre45 [30]

part 1 : the final volume : 1.404 L

part 2 : the initial concentration : 4.06 M

<h3>Further explanation </h3>

Dilution is the process of adding a solvent to get a more dilute solution.

The moles(n) before and after dilution are the same.

Can be formulated :

M₁V₁=M₂V₂

M₁ = Molarity of the solution before dilution  

V₁ = volume of the solution before dilution  

M₂ = Molarity of the solution after dilution  

V₂ = Molarity volume of the solution after dilution

part 1 :

M₁=44.8%

V₁=0.73 L

M₂=23.3%

\tt V_2=\dfrac{M_1.V_1}{M_2}\\\\V_2=\dfrac{44.8\times 0.73}{23.3}\\\\V_2=1.404~L

part 2 :

V₁=739 ml=0.739 L

V₂=1.5 L

M₂=2

\tt M_1=\dfrac{M_2.V_2}{V_1}\\\\M_1=\dfrac{2\times 1.5}{0.739}\\\\M_1=4.06

6 0
3 years ago
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