1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
ankoles [38]
3 years ago
5

What is the maximum number of electrons that can be identified with each of following sets of quantum numbers? If there are none

, enter 0.

Chemistry
1 answer:
vichka [17]3 years ago
5 0

Answer:

So, only one electron is there with n = 0, l = 0 and its quantum set is n = 0, l = 0, ml = 0, ms = -1/2. Hope, this is helping. The maximum number of electrons that can fit inside a 'n' shell is 2n^2. So it would be 1.

Explanation:

You might be interested in
What is a wave produced by vibrating electric charges that can travel in matter and empty space?
Harman [31]
The answer is A

Explanation:
8 0
3 years ago
Read 2 more answers
What are the classes of alkanol
LuckyWell [14K]
1-PRIMARY ALKANOL 2-SECONDARY ALKANOL 3-TERTIARY ALKANOL
8 0
4 years ago
The combustion of ethene in the presence of excess oxygen yields carbon dioxide and water: c2h4 (g) + 3o2 (g) → 2co2 (g) + 2h2o
meriva

Answer:

\boxed{-267.5}

Explanation:

You can calculate the entropy change of a reaction by using the standard molar entropies of reactants and products.

The formula is

\Delta_{r} S^{\circ} = \sum_n {nS_{\text{products}}^{\circ} - \sum_{m} {mS_{\text{reactants}}^{\circ}}}

The equation for the reaction is

                        C₂H₄(g) + 3O₂(g) ⟶ 2CO₂(g) + 2H₂O(ℓ)

ΔS°/J·K⁻¹mol⁻¹   219.5      205.0         213.6         69.9

\Delta_{r} S^{\circ} = (2\times213.6 + 2\times69.9) - (1\times219.5 + 3\times205.0)\\\\= 567.0 - 834.5 = \boxed{-267.5 \text{ J}\cdot\text{K}^{-1} \text{mol}^{-1}}

3 0
3 years ago
Use the reaction given below to solve the problem that follows: Calculate the mass in grams of aluminum oxide produced by the re
bearhunter [10]

Answer:  28.4 g of aluminum oxide is produced by the reaction of 15.0 g of aluminum metal

Explanation:

To calculate the moles :

\text{Moles of solute}=\frac{\text{given mass}}{\text{Molar Mass}}   

\text{Moles of} Al=\frac{15.0g}{27g/mol}=0.556moles

The balanced chemical equuation is:

4Al+3O_2\rightarrow 2Al_2O_3  

According to stoichiometry :

4 moles of Al produce == 2 moles of Al_2O_3

Thus 0.556 moles of Al will produce=\frac{2}{4}\times 0.556=0.278moles  of Al_2O_3

Mass of Al_2O_3=moles\times {\text {Molar mass}}=0.278moles\times 102g/mol=28.4g

Thus 28.4 g of aluminum oxide is produced by the reaction of 15.0 g of aluminum metal.

7 0
3 years ago
When the equal molar amounts of of both the acid and the base were reacts, what happened in the reaction?
Advocard [28]
It is going to be reaction of neutralization, and water and salt will be formed. If acid and base are strong, the reaction of the solution should become neutral.
3 0
4 years ago
Other questions:
  • What mass of manganese(II) chloride must react with sulfuric acid to release 52.5 mL of hydrogen chloride gas at STP?
    12·1 answer
  • Which of the following is an example of a chemical change? Dissolving sugar in coffee Evaporating rubbing alcohol Freezing water
    13·2 answers
  • Why there is not reaction in nac2h3o2(aq)+pb(no3)2(aq)→?
    5·1 answer
  • the two amino acids, glycine and alanine, can form two different dipeptides. Draw one of the possible dipeptides as it would app
    9·1 answer
  • The volume of a gas depends upon its mass. <br><br>•True<br>•False
    5·2 answers
  • Which of the following processes involves only physical change? A. decay B. sublimation C. digestion D. combustion
    5·2 answers
  • What is not a guideline required for a valid evidence test?
    5·1 answer
  • Which statement correctly describes the location and charge of the electrons in an atom?
    6·1 answer
  • What is the density of an object with a mass of 140 g and a volume<br> of 6 ml
    7·1 answer
  • When bethany walks across a carpet her socks pick up many electric charges. Later in the day these charges are no longer present
    5·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!