Oxygen is important in the oxidation of glucose because it ____________________________. Oxygen is important in the oxidation of
1 answer:
You might be interested in
Answer:
(a) AL
(b) Sc
(c)Al
Explanation:
Ionization Energy is the energy required to remove electrons from the outer most orbitals of atom.
The higher the electron is on energy level the farther its from nucleus and more loosely bonded thus need lesser energy.
By looking at electron configuration we can figure out which electron will need more energy.
<h3>(a)Na, Mg, Al</h3>1s², 2s², 2p⁶, 3s², 3p⁶,4s², 3d¹
Na₁₁ ⇒ 1s², 2s², 2p⁶, 3s¹
Mg₁₂ ⇒ 1s², 2s², 2p⁶, 3s²
Al₁₃ ⇒ 1s², 2s², 2p⁶, 3s², 2p¹
Al will have lowest IE₃ as its third electron will be in highest energy level and more loosely bonded to nucleus.
<h3>(b) K, Ca, Sc</h3>K₁₉⇒1s², 2s², 2p⁶, 3s², 3p⁶,4s²
Ca₂₀⇒1s², 2s², 2p⁶, 3s², 3p⁶,4s²
Sc₂₁⇒1s², 2s², 2p⁶, 3s², 3p⁶,4s², 3d¹
Sc will have lowest IE₃ as its third electron will be in highest energy level and more loosely bonded to nucleus.
<h3>(c) Li, Al, B</h3>Li₃ ⇒ 1s², 2s¹
Al₁₃ ⇒ 1s², 2s², 2p⁶, 3s², 2p¹
B₅ ⇒ 1s², 2s², 2p¹
Al will have lowest IE₃ as its third electron will be in highest energy level and more loosely bonded to nucleus.
Answer:
Q is 0.5 and K is 0.01, therefore K is less than Q.
the system will proceed in the reverse direction, thereby converting products into reactants. converting Nitric oxide to form oxygen and nitrogen.
Explanation:
Given,
N2 (g) + O2 (g) « 2 NO (g)
K = 0.01
heated temperature = 2000 ⁰C
N2 moles =0.4
O2 moles =0.1
2NO moles = 0.08
Volume of container = 1L
Q is the reaction quotient of the equilibrium equation. it is use to determined which direction the system will move to by comparing it with the K value.
Q can be calculated by multiplication of mass of reactant divide by mass of product
Q =
the mass of the chemicals are in mole, there is need to convert them to moles/litre
therefore,
for N₂ : 0.4 mole per 1L container = 0.4 mol/L = 0.4M
for O₂ : 0.1 mole per 1L container = 0.1 mol/L = 0.1M
for 2NO : 0.08mole per 1L container = 0.08 mol/L = 0.08M
Q = = (0.4*0.1)/0.08 = 0.5
finally, we are going to compare the value of Q with K
Note that:
if K>Q , the reaction will proceed forward, converting reactants into product.
if K<Q , the reaction will proceed backward, converting products into reactants.
if K=Q , the system of reaction is already in equilibrium.
since, Q is 0.5 and K is 0.01, therefore K is less than Q.
the system will proceed in the reverse direction, thereby converting products into reactants. converting Nitric oxide to form oxygen and nitrogen.