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Ksenya-84 [330]
2 years ago
8

An ideal gas in a sealed container has an initial volume of 2.55 L. At constant pressure, it has cooled to 16.00 degrees Celcius

where its final volume is 1.75 L. What was the initial temperature?
Chemistry
1 answer:
kipiarov [429]2 years ago
7 0
Use ideal gas law PV=nRT. The pressure, number of moles, and gas constant are unchanged. Rearrange ideal gas law to get n= PV1/RT1= PV2/RT2 now you can cancel out P and R to get V1/T1 = V2/T2 you know V1= 2.55 L, V2= 1.75 L, T2= 16 degC, you can solve for T1( the initial temperature).
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Taking advantage of their large differences in pKa values, describe how a mixture of phenol and benzoic acid in diethyl ether so
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Having the two layers separated, the benzoic acid can be recovered from the aqueous layer by adding HCl:

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<u>This acid will precipitate from the aqueous solution, and the solid can be isolated by filtration</u>.  

The phenol in the organic layer can be dissolved into an aqueous layer by the adding of a strong base like NaOH:

C₆H₅-OH + OH⁻  ⇄  C₆H₅-O⁻ + H₂O

The phenoxide ion soluble in the aqueous layer can be recovered later by the adding of HCl, which will form the original phenol:

C₆H₅-O⁻ + HCl  ⇄  C₆H₅-OH + Cl⁻  

<u>The precipitated phenol can be isolated by filtration. </u>

This way we can separate a mixture of phenol and benzoic acid in diethyl ether solution.  

I hope it helps you!

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