Question

A 750.0 mL solution contains 5.00 g of NaOH. If the molar mass of NaOH is 39.9969 g/mol, what is the molarity of the solution?

Answer 1

Answer: Option (b) is the correct answer.

Explanation:

To find molarity, firstly we need to calculate number of moles as follows.

   No. of moles = $\frac{mass given}{molar mass}$

                          = $\frac{5.00 g}{39.9969 g/mol}$

                          =  $0.125 mol$

Therefore, molratity is defines as number of moles of solute present in liter of solution.

               Molarity = $\frac{no. of moles of solute}{Volume of solution}$

                              = $\frac{0.125 mol}{0.75 L}$

                              = $0.167 mol L^{-1}$

Thus, we can conclude that molarity of solution is $0.167 mol L^{-1}$.

Answer 2

Answer:

option b is correct

Explanation: