<span>the balanced equation for the reaction is as follows
Na</span>₂<span>SO</span>₄<span> + BaCl</span>₂<span> ----> 2NaCl + BaSO</span>₄
<span>stoichiometry of Na</span>₂<span>SO</span>₄<span> to BaCl</span>₂<span> is 1:1
first we need to find out which the limiting reactant is
limiting reactant is fully used up in the reaction.
number of Na2So4 moles - 0.5 mol number of BaCl2 moles - 60 g / 208 g/mol = 0.288 mol
since molar ratio is 1:1 equal number of moles of both reactants should react with each other
therefore BaCl2 is the limiting reactant and Na2SO4 is in excess. amount of product formed depends on number of limiting reactant present.
stoichiometry of BaCl</span>₂<span> to BaSO</span>₄<span> is 1:1.
therefore number of BaSO4 moles formed - 0.288 mol</span>
Answer:
808
Step-by-step explanation:
One serving of Original Pringles = 28 g = 150 Cal
Pringles ⟶ Cal 50 g × (150 Cal/28 g) = 268 Cal
Cal ⟶ J 268 Cal × (4184 J/1 Cal) = 1.121 × 10⁶ J
J ⟶ N·m 1.121 × 10⁶ J × (1 N·m/1 J) = 1.121 × 10⁶ N·m
N·m ⟶ m 1.126 × 10⁶ N·m/455N = 2460 m
m ⟶ km 2460 m × (1 km/1000 m) = 2.46 km
km ⟶ mi 2.46 km × (0.6214 mi/1 km) = 1.53 mi
mi ⟶ ft 1.53 mi ×(5280 ft/1 mi) = 8080 ft
ft ⟶ flights 8080 ft × (1 flight/10 ft) = 808 flights
The student would have to climb 808 flights of stairs to burn off the energy from 50 g of Pringles [that's equivalent to climbing the stairs in the Salesforce Tower (1070 ft) in San Francisco about 7½ times].
Answer: 120.9 grams
Explanation:
Given the question : How many grams are in 3.67 moles of Lithium cyanide?
Chemical formula of lithium cyanide = LiCN
Molar mass of LiCN: Li = 6.941 ; C = 12, N = 14
LiCN = (6.941 + 12 + 14). = 32.941 g/mol
(Gram of substance / mole of substance) = (molar mass of substance / one mole)
(Gram of substance / 3.67) = (32.941 / 1)
= gram * 1 = 3.67 * 32.941
Gram of substance = 120.89347
= 120.9 grams
Answer:
The net chemical equation for the production of iron from carbon, oxygen and iron(III) oxide:
Explanation:
Step 1: Carbon and oxygen react to form carbon monoxide:
..[1]
Step 2: Iron(III) oxide and carbon monoxide react to form iron and carbon dioxide:
..[2]
The net chemical equation for the production of iron from carbon, oxygen and iron(III) oxide can be obtained by :
3 × [1] + 2 × [2]
CO gas will gas cancel out form both sides ans we will get the net chemical equation:
According to reaction, 2 moles of ferric oxide reacts with 6 moles of carbon and 3 moles of oxygen gas to give 4 moles of iron and 6 moles pf carbon dioxide gas.
Answer: 0.25 g
I just took this test and that was the answer to it.
