Answer:
The range of powers is 
Explanation:
From the question we are told that
The far point of the left eye is 
The near point of the left eye is 
The near point with the glasses on is 
From these parameter we can see that with the glass on that for near point the
Object distance would be 
Image distance would be 
To obtain the focal length we would apply the lens formula which is mathematically represented as
substituting values
converting to meters
Generally the power of the lens is mathematically represented as
Substituting values
From these parameter we can see that with the glass on that for far point the
Object distance would be 
Image distance would be 
To obtain the focal length of the lens we would apply the lens formula which is mathematically represented as
substituting values
converting to meters
Generally the power of the lens is mathematically represented as
Substituting values
This implies that the range of powers of the lens in his glass is
-- Starting from nothing (New Moon), the moon's shape grows ('waxes')
for half of the cycle, until it's full, and then it shrinks ('wanes') for the next
half of the cycle.
-- The moon's complete cycle of phases runs 29.53 days . . . roughly
four weeks.
-- So, beginning from New Moon, it spends about two weeks waxing until
it's full, and then another two weeks waning until it's all gone again.
-- After a Full Moon, the moon is waning for the next two weeks. So it's
definitely <em>waning</em> at <em><u>one week</u></em> after Full.
Answer:
Option B. Decreases
Explanation:
Coulomb's law states that:
F = Kq₁q₂ / r²
Where:
F => is the force of attraction between two charges
K => is the electrical constant.
q₁ and q₂ => are the two charges
r => is the distance apart.
From the formula:
F = Kq₁q₂ / r²
The force of attraction (F) is inversely proportional to the square of their separating distance (r).
This implies that as the distance between them increase, the force of attraction between the two charges will decrease and as the distance between two charges decrease, the force of attraction between them will increase.
Considering the question given above and the illustration given above, the force of attraction will decrease as their distance of separation increases.
Option B gives the right answer to the question.
Answer:
1.23 m
Explanation:
The vertical distance covered by a free-falling object starting from rest in a time t is
where
g = 9.8 m/s^2 is the acceleration due to gravity
In this problem, we have
t = 0.50 s
So the distance covered is
Objects with Relative density greater than 1 will sink in water. As you can see here, solution has density greater than 1( density = mass/volume = 43/35 = 1.22 g/ml). Hence solution will suspend at the bottom of the beaker. So option A is correct. Hope this cleared your doubt!
