<span>The substance that is produced at the cathode during the electrolysis of a mixture of molten calcium bromide, cabr2(I), and molten magnesium iodide, mgi2(I), can be expressed as Ca2+ + 2eâ’ --> Ca. At the anode, the substance can be expressed as 2Brâ’ â’ 2eâ’ --> Br2. At the cathode for magnesium iodide can be expressed as Mg2+ + 2 eâ’ --> Mg, and 2 Iâ’ â’ 2 eâ’ --> I2 at the anode.</span>
Answer:
S + 02= S0 - 4 e- → SIV (oxidation); 2 O0 + 4 e- → 2 O-II (reduction)
C + 02= C
Cu0 + H2SO4= CuO + H2SO4 → CuSO4 + H2O
A. Protons and Neutrons will get u the atomic mass.
<span>Because its a Chemical combination of 2 different pure Elements, it's a Compound. </span>