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Colt1911 [192]
3 years ago
15

To form a stable ion will magnesium gain or lose electrons how many electrons

Chemistry
1 answer:
pashok25 [27]3 years ago
4 0
The electronic structure of Magnesium is 2,8,2
so in order to form a stable ions, it will lose 2 electrons.
Now, the proton number of Mg is 12, electron number is 10.
It will show positive charge.
Conclusion: Mg will lose 2 electrons to form Mg2+. 
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tis is a math question

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If an equal mass of sugar and aluminum were poured into separate containers, which would require the smaller container?
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Read 2 more answers
The volume of an automobile air bag was 66.8 L when inflated at 25 °C with 77.8 g of nitrogen gas. What was the pressure in the
Ray Of Light [21]

Answer:

\large \boxed{\text{103 kPa}}

Explanation:

We can use the Ideal Gas Law — pV = nRT

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(b) Convert the temperature to kelvins

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(c) Calculate the pressure

\begin{array}{rcl}pV & =& nRT\\p \times \text{66.8 L} & = & \text{2.778 mol} \times \text{8.314 kPa$\cdot$ L$\cdot$K$^{-1}$mol$^{-1}\times$ 298.15 K}\\66.8p & = & \text{6886 kPa}\\p & = & \textbf{103 kPa}\end{array}\\\text{The pressure in the bag is $\large \boxed{\textbf{103 kPa}}$}

3 0
3 years ago
The ease which an acid or base dissociates in a solution refers to
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Answer:

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5 0
3 years ago
30 POINTS PLEASE HELP ASAP
lina2011 [118]

Hello!

We have the following data:

f (radiation frequency) = 3.0*10^{19}\:Hz

v (speed of light) = 3.0*10^8\:m/s

λ (wavelength) = ? (in m)

Let's find the wavelength, let's see:

f = \dfrac{v}{\lambda}

3.0*10^{19} = \dfrac{3.0*10^8}{\lambda}

\lambda = \dfrac{3.0*10^8}{3.0*10^{19}}

\boxed{\boxed{\lambda = 1*10^{-11}\:m}}\Longleftarrow(wavelenght)\end{array}}\qquad\checkmark

I Hope this helps, greetings ... DexteR! =)

4 0
3 years ago
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