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mr_godi [17]
3 years ago
10

If your going down a hill what type of energy are you making?

Chemistry
2 answers:
kow [346]3 years ago
6 0

Answer:

Gravitational potential energy - into Kinetic energy

Explanation:

Andrei [34K]3 years ago
3 0
Answer is kinetic energy
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What is the mass of 3.6 x 10∧24 atoms of Zinc (Zn)?
Sauron [17]
If that in the middle between the 10 and 24 is a caret, then I believe this is the work:

3.6 x 10^24 atoms Zn / 6.022x10^23 atom/mol Zn = 6 mol Zn

6 mol Zn x 65.36 g/mol Zn = 390 g Zn if you carry two significant figures with rounding at each step.

I believe that is correct as all the units cancel properly.
3 0
4 years ago
The water has a mass of 480.0 grams. If you drink 200.0 grams of the water, how many molecules of water remain in the glass?
Ne4ueva [31]

Answer:

55641.656 × 10^23 molecules

Explanation:

Get the molar mass, multiply by amount of stuff, multiply by Avogadros number.

More detail in picture attached.

Hope it helps. Brainliest Appreciated. :)

8 0
2 years ago
Using the table of standard formation enthalpies that you'll find under the ALEKS Data tab, calculate the reaction enthalpy of t
Natasha2012 [34]
Hard question !! Is this math .. if not then oh okay cause I’m bad at math but good at everything else so let me think about it !
7 0
3 years ago
On average what is the time between collisions of a xenon atom at 300 K and (a) one torr pressure; (b) one bar pressure.
Amanda [17]

Answer:

(a). 132 × 10^-9 s = 132 nanoseconds.

(b)..176.5 pico-seconds.

Explanation:

(a). At one torr, the first thing to do is to find the speed and that can be done by using the formula below;

Speed = [ (8 × R × T)/ Mm × π]^1/2.

Where Mm = molar mass, T = temperature and R = gas constant.

Speed= [ ( 8 × 8.314 × 300)/ 131.293 × π × 10^-3)^1/2. = 220m/s.

The next thing to do now is to calculate for the degree of collision which can be calculated by using the formula below;

Degree of collision = √2 × π × speed × d^2 × pressure/ K × T.

Note that pressure = 1 torr = 133.32 N/m^2 and d = collision diameter.

Degree of collision = √2 × π × 220 × (4.9 × 10^-10)^2 × 133.32/ 1.38 × 10^-23 × 300.

Degree of collision = 7.55 × 10^6 s^-1.

Thus, 1/ 7.55 × 10^6. = 132 × 10^-9 s = 132 nanoseconds.

(b). At one bar;

1/10^5 × 10^3 × 56.65 = 1.765 × 10^-10 = 176.5 pico-seconds.

6 0
3 years ago
What is the number of neutrons is one atom of carbon?
antoniya [11.8K]

Carbon atoms have 6 neutrons.


<em>I hope this helped you out!! Happy thanksgiving! </em>

5 0
3 years ago
Read 2 more answers
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