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Ludmilka [50]
3 years ago
6

The abc battery company claims that their batteries last 100 hours, on average. you decide to conduct a test to see if the compa

ny's claim is true. you believe that the mean life may be different from the 100 hours the company claims. you decide to collect data on the average battery life (in hours) of a random sample of n = 20 batteries. some of the information related to the hypothesis test is presented below.

Physics
1 answer:
taurus [48]3 years ago
6 0

Complete question is;

The abc battery company claims that their batteries last 100 hours, on average. You decide to conduct a test to see if the company's claim is true. You believe that the mean life may be different from the 100 hours the company claims. you decide to collect data on the average battery life (in hours) of a random sample of n = 20 batteries. some of the information related to the hypothesis test is presented below:

Test of H0: μ = 100 versus H1: μ ≠ 100

Sample mean: 98.5

Std error of mean: 0.777

Assuming the life length of batteries is normally distributed, what is the p-value associated with this test?

Answer:

p-value =  0.00001

Explanation:

We are given;

Null hypothesis; H0: μ = 100

Alternative Hypothesis; H1: μ ≠ 100

Sample mean: x = 98.5

Standard error of mean; s = 0.777

To find the test statistic, we will use the formula;

t = (x - μ)/(s/√n)

t = (98.5 - 100)/(0.777/√20)

t = -1.5/0.1737

t = -8.64

Now, from online p-value from t-score calculator attached, using t = -8.64; DF = n - 1 = 20 - 1 = 19; two tail distribution;significance level of 0.05; we have;

The p-value =  0.00001

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Answer:

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3 years ago
A 5.0 kg block hangs from the ceiling by a mass-less rope. A Second block with a mass of 10.0 kg is attached to the first block
gayaneshka [121]

The tension in the first and second rope are; 147 Newton and 98 Newton respectively.

Given the data in the question

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To find the Tension in each of the ropes, we make use of the equation from Newton's Second Laws of Motion:

F = m\ *\ a

Where F is the force, m is the mass of the object and a is the acceleration ( In this case the block is under gravity. Hence ''a" becomes acceleration due to gravity  g = 9.8m/s^2 )

For the First Rope

Total mass hanging on it; m_T = m_1 + m_2 = 5.0kg + 10.0kg = 15.0kg

So Tension of the rope;

F = m\ * \ g\\\\F = 15.0kg \ * 9.8m/s^2\\\\F = 147 kg.m/s^2\\\\F = 147N

Therefore, the tension in the first rope is 147 Newton

For the Second Rope

Since only the block of mass 10kg is hang from the second, the tension in the second rope will be;

F = m\ * \ g\\\\F = 10.0kg \ * 9.8m/s^2\\\\F = 98 kg.m/s^2\\\\F = 98N

Therefore, the tension in the second rope is 98 Newton

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In this problem, the original force between the two objects is F, when they are separated by a distance r.

Later, the distance between the two objects is doubled, so the new distance is

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