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Artyom0805 [142]
3 years ago
8

A bar magnet is dropped from above and falls through the loop of wire. The north pole of the bar magnet points downward towards

the page as it falls. Which statement is correct?a. The current in the loop always flows in a clockwise direction. b·The current in the loop always flows in a counterclockwise direction. c. The current in the loop flows first in a clockwise, then in a counterclockwise direction. d. The current in the loop flows first in a counterclockwise, then in a clockwise direction. e. No current flows in the loop because both ends of the magnet move through the loop.
Physics
1 answer:
8_murik_8 [283]3 years ago
3 0

Answer:

<em>b. The current in the loop always flows in a counterclockwise direction.</em>

<em></em>

Explanation:

When a magnet falls through a loop of wire, it induces an induced current on the loop of wire. This induced current is due to the motion of the magnet through the loop, which cause a change in the flux linkage of the magnet. According to Lenz law, the induced current acts in such a way as to repel the force or action that produces it. For this magnet, the only opposition possible is to stop its fall by inducing a like pole on the wire loop to repel its motion down. An induced current that flows counterclockwise in the wire loop has a polarity that is equivalent to a north pole on a magnet, and this will try to repel the motion of the magnet through the coil. Also, when the magnet goes pass the wire loop, this induced north pole will try to attract the south end of the magnet, all in a bid to stop its motion downwards.

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Four traveling waves are described by the following equations, where all quantities are measured in SI units and y represents th
agasfer [191]

Answer:

T_1=T_3=\dfrac{2\pi}{21}

T_2=T_4=\dfrac{2\pi}{42}

Explanation:

Wave 1, y_1=0.12\ cos(3x-21t)

Wave 2, y_2=0.15\ sin(6x+42t)

Wave 3, y_3=0.13\ cos(6x+21t)

Wave 4, y_4=-0.27\ sin(3x-42t)

The general equation of travelling wave is given by :

y=A\ cos(kx\pm \omega t)

The value of \omega will remain the same if we take phase difference into account.

For first wave,

\omega_1=21

\dfrac{2\pi }{T_1}=21

T_1=\dfrac{2\pi}{21}

For second wave,

\omega_2=42

\dfrac{2\pi }{T_2}=42

T_2=\dfrac{2\pi}{42}

For the third wave,

\omega_3=21

\dfrac{2\pi }{T_3}=21

T_3=\dfrac{2\pi}{21}

For the fourth wave,

\omega_4=42

\dfrac{2\pi }{T_4}=42

T_4=\dfrac{2\pi}{42}

It is clear from above calculations that waves 1 and 3 have same time period. Also, wave 2 and 4 have same time period. Hence, this is the required solution.

3 0
3 years ago
High speed stroboscopic photographs show that the head of a 244 g golf club is traveling at 57.6 m/s just before it strikes a 45
almond37 [142]

Answer:

The speed will be "1.06 m/s".

Explanation:

The given values are:

Momentum,

m1 = 244 g

m2 = 45.2 g

On applying momentum conservation ,

Let v2 become the final golf's speed.  

From Momentum Conservation

⇒  Total \ initial \ momentum = Total \ final \ momentum

⇒  m1\times u1 + m2\times u2 = m1\times v1 + m2\times v2

On putting the estimated values, we get

⇒  0.244\times 57.6+0=0.244\times 39.9+45.2\times v2

⇒  57.844+0=9.7356+45.2\times v2

⇒  48.1084=45.2\times v2

⇒  v2=\frac{48.1084}{45.2}

⇒  v2=1.06 \ m/s

6 0
3 years ago
Andrew and Warren sit on opposite sides of a table of mass 28 kg. Andrew pushes the table to the right with a force of 277 N, an
Ostrovityanka [42]

The acceleration is 2.2 m/s^2 and the net force is  62N towards the right

<h3>What is the net force?</h3>

The net force is the effective force that acts on a body in a give direction.

1. The net force in the y axis is; ∑Fy = 0

2. The net force along the y axis is; ∑Fx =  277 N - 215 N

3. The normal reaction is given by;  28 kg * 9.8 m/s^2 = 274.4 N

4. The net force in the x axis is  277 N - 215 N = 62N towards the right

5. The acceleration of this force is obtained from;

F = ma

62 = 28 a

a = 62/28

a = 2.2 m/s^2

Learn more about the net force:brainly.com/question/18031889

#SPJ1

4 0
2 years ago
The law of conservation of momentum of two interacting objects that make up a system
Aleonysh [2.5K]
The law of conservation of momentum states that, if left alone, the total momentum of two interacting objects that make up a system remains the same.
6 0
3 years ago
What role does friction play in the conservation of enérgy?
Alja [10]

The law of conservation of energy asserts that total energy remains constant in an isolated system. That is, energy cannot be generated or destroyed, but it may be transferred from one form to another. Frictional forces can dissipate energy, which raises the question of whether it violates the law of conservation of energy. No, it does not. When there is friction, energy is transferred from one form to another. There will be no energy loss. To illustrate this issue, consider the following scenario: two buses collide. The buses are no longer moving as a result of the collision. Where does all of this energy go? The solution is simple: the friction between buses and between buses and the road allows energy to be transferred from one form to another. You may be aware that when we rub our hands together, heat is produced; what occurs here is frictional energy converting to heat energy. This is what happens in bus accidents, where the energies can be changed to thermal energy, acoustic energy, or any other type of energy owing to friction and impact. So the energy we believed we had wasted was really converted to heat and sound. Bus collisions are not only noisy, but they also cause a lot of friction on the ground and in the bent metal. Both heat and sound are types of energy.

  • NOTE:
    Nature's exact rules cannot be broken. The law of conservation of energy is an example of such a law. Friction constantly resists relative motion between two surfaces in contact.
7 0
2 years ago
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