Question

High speed stroboscopic photographs show that the head of a 244 g golf club is traveling at 57.6 m/s just before it strikes a 45.2 g golf ball at rest on a tee. After the collision, the club head travels (in the same direction) at 39.9 m/s. Find the speed of the golf ball just after impact.

Answer 1

Answer:

The speed will be "1.06 m/s".

Explanation:

The given values are:

Momentum,

m1 = 244 g

m2 = 45.2 g

On applying momentum conservation ,

Let v2 become the final golf's speed.  

From Momentum Conservation

⇒  $Total \ initial \ momentum = Total \ final \ momentum$

⇒  $m1\times u1 + m2\times u2 = m1\times v1 + m2\times v2$

On putting the estimated values, we get

⇒  $0.244\times 57.6+0=0.244\times 39.9+45.2\times v2$

⇒  $57.844+0=9.7356+45.2\times v2$

⇒  $48.1084=45.2\times v2$

⇒  $v2=\frac{48.1084}{45.2}$

⇒  $v2=1.06 \ m/s$