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-Dominant- [34]
2 years ago
7

What role does friction play in the conservation of enérgy?

Physics
1 answer:
Alja [10]2 years ago
7 0

The law of conservation of energy asserts that total energy remains constant in an isolated system. That is, energy cannot be generated or destroyed, but it may be transferred from one form to another. Frictional forces can dissipate energy, which raises the question of whether it violates the law of conservation of energy. No, it does not. When there is friction, energy is transferred from one form to another. There will be no energy loss. To illustrate this issue, consider the following scenario: two buses collide. The buses are no longer moving as a result of the collision. Where does all of this energy go? The solution is simple: the friction between buses and between buses and the road allows energy to be transferred from one form to another. You may be aware that when we rub our hands together, heat is produced; what occurs here is frictional energy converting to heat energy. This is what happens in bus accidents, where the energies can be changed to thermal energy, acoustic energy, or any other type of energy owing to friction and impact. So the energy we believed we had wasted was really converted to heat and sound. Bus collisions are not only noisy, but they also cause a lot of friction on the ground and in the bent metal. Both heat and sound are types of energy.

  • NOTE:
    Nature's exact rules cannot be broken. The law of conservation of energy is an example of such a law. Friction constantly resists relative motion between two surfaces in contact.
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It is 500000 kg in 0.5 mg
5 0
3 years ago
A paintball is fired horizontally from a tower 45 m above the ground. If the paintball gun fires at 90 m/s… How long does it tak
ankoles [38]

Answer:

The time taken for the paint ball to hit the ground is t =  2.143 \ s

The distance of the landing point from the tower is d = 192.86 \  m

Explanation:

From the question we are told that

   The height of the tower is h =  45 \ m

    The speed of the paintball in the horizontal direction is  v_x =  90 \  m/s

Generally from kinematic equation we have that

      h =  ut + \frac{1}{2} at^2

Here u is the initial  velocity of the paintball in the vertical direction and the value is 0 m/s , this because the ball was fired horizontally

         a is equivalent to g  = 9.8\ m/s^2

        t is the time taken for the paintball to hit the ground

   So    

       45  =  0* t + \frac{1}{2} 9.8 * t^2

=>    t =  2.143 \ s

Generally the distance of its landing position from the tower is

         d = v  *  t

=>      d = 90 *  2.143

=>    d = 192.86 \  m

     

3 0
3 years ago
Simon is riding a bike at 12 km/h away from his friend Keesha. He throws a ball at 5 km/h back to Keesha, who is standing still
pychu [463]
So there are different ways this could be solved. I'll do try to explain it the way I was taught... 

Simon is riding his bike at 12 km/hr relative to the sidewalk, away from where Keesha is.

Simon throws the ball at Keesha, at 5 km/hr. 

Keesha sees the ball approaching her at (12-5) = 7 km/hr relative to the ground to her. 

Therefore the answer is: 7 km/hr


3 0
3 years ago
Octane is an important component of gasoline. Octane will ignite at a temperature of 428°F. What is this temperature on the Cels
xxMikexx [17]
The requirement is to change the °F to °C scale. That is;

T(°C) = [T(°F) - 32]/1.8

Substituting;

T(°C) = [428 - 32]/1.8 = 396/1.8 = 220 °C.

Therefore, 428°F will be 220°C on Celsius scale.
5 0
4 years ago
A magnet in the form of a cylindrical rod has a length of 7.30 cm and a diameter of 1.5 cm. It has a uniform magnetization of 5.
yulyashka [42]

Answer:

Magnetic dipole moment is 0.0683 J/T.

Explanation:

It is given that,

Length of the rod, l = 7.3 cm = 0.073 m

Diameter of the cylinder, d = 1.5 cm = 0.015 m

Magnetization, M=5.3\times 10^3\ A/m

The dipole moment per unit volume is called the magnetization of a magnet. Mathematically, it is given by :

M=\dfrac{\mu}{V}

\mu=M\times \pi r^2\times l

Where

r is the radius of rod, r = 0.0075 m

\mu=5.3\times 10^3\ A/m\times \pi (0.0075)^2\times 0.073\ m

\mu=0.0683\ J/T

So, its magnetic dipole moment is 0.0683 J/T. Hence, this is the required solution.

6 0
3 years ago
Read 2 more answers
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