4 moles of water are produced
Explanation:
- 4 moles of water are produced when 5 moles of hydrogen is reacted with 2 moles of oxygen gas
- The balanced equation given is when 2 moles of hydrogen reacts with 1 mole of oxygen and it forms 2 moles of water.
- The equation we have to solve is the 5 moles of hydrogen is reacting with 2 moles of oxygen gas, we can write the equation as
- This is the balanced equation when 5 moles of hydrogen reacts with 2 moles of oxygen. The balanced equation means the number of hydrogen atoms and oxygen atoms on both sides would be equal in number.
Answer:
Concentration of sodium carbonate in the solution before the addition of HCl is 0.004881 mol/L.
Explanation:
Molarity of HCl solution = 0.1174 M
Volume of HCl solution = 83.15 mL = 0.08315 L
Moles of HCl = n
According to reaction , 2 moles of HCl reacts with 1 mole of sodium carbonate.
Then 0.009762 mol of HCl will recat with:
Moles of Sodium carbonate = 0.004881 mol
Volume of the sodium carbonate containing solution taken = 1L
Concentration of sodium carbonate in the solution before the addition of HCl:
![[Na_2CO_3]=\frac{0.004881 mol}{1 L}=0.004881 mol/L](https://tex.z-dn.net/?f=%5BNa_2CO_3%5D%3D%5Cfrac%7B0.004881%20mol%7D%7B1%20L%7D%3D0.004881%20mol%2FL)
When heat is added to a substance, the molecules and atoms vibrate faster. As atoms vibrate faster, the space between atoms increases.
I looked online and I found that it is <span>1X10 to the power of -22 grams.</span>
Answer:
7.86 moles of sodium chloride are produced.
Explanation:
Given data:
Moles of chlorine = 3.93 mol
Amount of sodium = excess
Moles of sodium chloride formed = ?
Solution:
Chemical equation:
2Na + Cl₂ → 2NaCl
Now we will compare the moles of sodium chloride with chlorine.
Cl₂ : NaCl
1 : 2
3.93 : 2×3.93 = 7.86
Chlorine is limiting reactant that's why we compare the NaCl with only number of mole of chlorine.
Thus, 7.86 moles of sodium chloride are produced.
