Try G I think I’m correct
Answer: see below
<u>Explanation:</u>
When multiplying or dividing, use the smallest number of significant figures (sf) of the digits provided.
37(a) 24 × 3.26 = 78.24 <em>2 sf × 3 sf </em>--> round to 2 sf's
≈ 78
(b) 120 × 0.10 = 12 <em>2 sf × 2 sf </em>--> round to 2 sf's
= 12
(c) 1.23 × 2.0 = 2.46 <em>3 sf × 2 sf </em>--> round to 2 sf's
= 2.5
(d) 53 × 1.53 = 81.09 <em>2 sf × 3 sf </em>--> round to 2 sf's
= 81
38(a) 4.84 ÷ 2.4 = 2.0167 <em>3 sf × 2 sf </em>--> round to 2 sf's
= 2.0
(b) 60.2 ÷ 20.1 = 2.995 <em>3 sf × 3 sf </em>--> round to 3 sf's
= 3.00
(c) 102.4 ÷ 51.2 = 2 <em>4 sf × 3 sf </em>--> round to 3 sf's
= 2.00
(d) 168 ÷ 58 = 2.896 <em>3 sf × 2 sf </em>--> round to 2 sf's
= 2.9
Answer:
Concentration of sodium carbonate in the solution before the addition of HCl is 0.004881 mol/L.
Explanation:
Molarity of HCl solution = 0.1174 M
Volume of HCl solution = 83.15 mL = 0.08315 L
Moles of HCl = n
According to reaction , 2 moles of HCl reacts with 1 mole of sodium carbonate.
Then 0.009762 mol of HCl will recat with:
Moles of Sodium carbonate = 0.004881 mol
Volume of the sodium carbonate containing solution taken = 1L
Concentration of sodium carbonate in the solution before the addition of HCl:
Weathering is the process by which rocks are broken down by either physical or chemical means. Physical weathering involves physical factors that cause mechanical break down of rocks while chemical weathering involves chemical reactions between the contents of the rocks and other factors such air (oxygen). Agents of weathering are the factors that cause or enhance both physical and chemical weathering. Some of these factors cause both physical and chemical weathering these includes water and temperature.
The items are answered below and are numbered separately for each compound.
The freezing point of impure solution is calculated through the equation,
Tf = Tfw - (Kf)(m)
where Tf is the freezing point, Tfw is the freezing point of water, Kf is the freezing point constant and m is the molality. For water, Kf is equal to 1.86°C/m. In this regard, it is assumed that m as the unit of 0.25 is molarity.
1. NH4NO3
Tf = 0°C - (1.86°C/m)(0.25 M)(2) = -0.93°C
2. NiCl3
Tf = 0°C - (1.86°C/m)(0.25 M)(4) = -1.86°C
3. Al2(SO4)3
Tf = 0°C - (1.86 °C/m)(0.25 M)(5) = -2.325°C
For boiling points,
Tb = Tbw + (Kb)(m)
For water, Kb is equal to 0.51°C/m.
1. NH4NO3
Tb = 100°C + (0.51°C/m)(0.25 M)(2) = 100.255°C
2. NiCl3
Tb = 100°C + (0.51°C/m)(0.25 M)(4) = 100.51°C
3. Al2(SO4)3
Tb = 100°C + (0.51°C/m)(0.25 M)(5) = 100.6375°C