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kvv77 [185]
3 years ago
9

Which line represents a stationary object?

Physics
2 answers:
Arada [10]3 years ago
6 0
I believe the answer is B. Stationary usually means that the object is not moving. Line B is going straight which would indicate that the object is not moving. Therefore I am pretty sure the answer is B. Hope this helps! <3
sineoko [7]3 years ago
3 0

Answer:

I think its B but I may be wrong

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A disk-shaped grindstone of mass 3.0 kg and radius 8.0 cm is spinning at 600 rev/min. After the power is shut off, a man continu
kolbaska11 [484]

Answer:

τ=0.060 N.m

Explanation:

By kinematics:

\omega f = \omega o-\alpha*t

Solving for α:

\alpha=\frac{\omega o-\omega f}{t}

where ωo = 600*2*π/60;   ωf = 0;    t=10s

\alpha=6.283rad/s^2

The sum of torque is:

\tau=I*\alpha

\tau=M*R^2/2*\alpha

\tau=0.060 N.m

8 0
3 years ago
Explain what would happen to the air temperature at Riverdale School if the groundwater system were used. Use the terms stabilit
Sergio039 [100]

OK.

But first we need to know . . .

-- Where is Riverdale ?

-- What is the air temperature there right now ?

-- What kind of system is being used now ?

-- Where can we get a complete description of the groundwater system ?

5 0
3 years ago
Read 2 more answers
The height of the empire state building is 318 m if a stone is dropped from the top of the building what is the stones velocity
lutik1710 [3]

79 m/s. A stone dropped from the top of the Empire State Building will have a velocity of 79 m/s just before it strikes the ground.

This problem is about free fall, to find the velocity of the stone before it strikes the ground we have to use the equation v_{f}^{2}=v_{0}^{2}+2gh, the initial velocity  of the stone is 0 m/s. Then:

v_{f}^{2}=2gh

v_{f}=\sqrt{ 2gh}

Solving the equation above with g = 9.8 m/s², and h = 318.0 m:

v_{f}=\sqrt{ 2(9.8m/s^{2})(318.0m)}= 78.95 m/s

v_{f}≅ 79 m/s

4 0
2 years ago
If I have a 10 lb ball and a 2 lb ball which
mojhsa [17]

Answer:

It would be the 10 lb ball.

Explanation:

The more that an object weighs, the more force that is needed to accelerate it.

Hope this helped

:)

6 0
3 years ago
0.180-kg stone rets on a frictionless, horizontal surface. A bullet of mass 7.50 g, traveling horizontally at 390 m/s, strikes t
Musya8 [376]

Answer:

The magnitud of the velocity is

8.46m/s

and the direccion:

-28.3 degrees from the horizontal.

Explanation:

Fist we define our variables:

m_{s}=0.18kg\\m_{b}=7.5g = 0.0075kg\\v_{1b}= 390m/s -i\\v_{1s}=0m/s\\v_{2b}=210m/s -j\\v_{2s}=?

The letters i and j represent the direction of the movement, i in this case is the horizontal direction, and j is perpendicular to i.

velocities with sub-index 1 are the speeds before the crash, and with sub-index 2 are the velocities after the crash.

Using conservation of momentum:

m_{s}v_{1s}+m_{b}v_{1b}=m_{s}v_{2s}+m_{b}v_{2b}\\v_{1s}=0, so\\m_{b}v_{1b}=m_{s}v_{2s}+m_{b}v_{2b}

Clearing for the velocity of the stone after the crash:

v_{2s}=\frac{m_{b}v_{1b}-m_{b}v_{2b}}{m_{s}}

Substituting known values:

v_{2s}=\frac{0.0075kg(((390m/s-i)-210m/s-j)}{0.18kg}\\v_{2s}=(16.25m/s-i) - (8.75m/s-j)

The magnitud of the velocity is :

|v_{2s}|=\sqrt{(16.25m/s-i)^2 + (8.75m/s-j)^2}\\|v_{2s}|=18.46m/s

and the direction:

tan^{-1}(-8.75/16.25)=-28.3

this is -28.3 degrees from the +i direction or the horizontal direcction.

Note: i and j can also be seen as x and y axis.

3 0
3 years ago
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