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Semmy [17]
4 years ago
14

The lowest possible frequency that can form in a musical instrument is called the _____. A fundamental frequency B the harmonic

C the second harmonic D the last harmonic
Physics
1 answer:
NeX [460]4 years ago
5 0
Perhaps D. if it is the lowebsr possible frequency then it would most likely be the last. I may not be 100 percent right, but that's just an educated guess.
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What behavior of light proves that it is a wave? Hint: will this ONLY happen because light is a wave, or could it also be true o
kiruha [24]
It’s red shift and blue shift because This only occurs when the frequency of the wave is made longer or shorter due to the movement of the source relative to the observer
4 0
3 years ago
A 26.0 g ball is fired horizontally with initial speed v0 toward a 110 g ball that is hanging motionless from a 1.10 m -long str
mart [117]

Answer:

7.3 ms^{-1}

Explanation:

Consider the motion of the ball attached to string.

In triangle ABD

Cos50 = \frac{AB}{AD} \\Cos50 = \frac{AB}{L}\\AB = L Cos50

height gained by the ball is given as

h = BC = AC - AD \\h = L - L Cos50\\h = 1.10 - 1.10 Cos50\\h = 0.393 m

M  = mass of the ball attached to string = 110 g

V = speed of the ball attached to string just after collision

Using conservation of energy

Potential energy gained = Kinetic energy lost

Mgh = (0.5) M V^{2} \\V = sqrt(2gh)\\V = sqrt(2(9.8)(0.393))\\V = 2.8 ms^{-1}

Consider the collision between the two balls

m  = mass of the ball fired = 26 g

v_{o} = initial velocity of ball fired before collision = ?

v_{f} = final velocity of ball fired after collision = ?

using conservation of momentum

m v_{o} = MV + m v_{f}\\26 v_{o} = (110)(2.8) + 26 v_{f}\\v_{f} = v_{o} - 11.85

Using conservation of kinetic energy

m v_{o}^{2} = MV^{2} + m v_{f}^{2} \\26 v_{o}^{2} = 110 (2.8)^{2} + 26 (v_{o} - 11.85)^{2} \\v_{o} = 7.3 ms^{-1}

3 0
3 years ago
A forward-biased silicon diode is connected to a 6.0-V battery. Also in the circuit are three 220 Ω resistors connected in serie
o-na [289]

Answer:

Current in the circuit will be 0.024 A

Explanation:

We have given battery voltage v = 6 volt

Resistance R = 220 ohm

Diode potential v_d = 0.7 volt

So voltage across the resistance = 6 - 0.7 = 5.3 volt

Current is given by current=\frac{voltage}{reistance}=\frac{5.3}{220}=0.024A

So current in the circuit will be 0.024 A

3 0
3 years ago
When evaluating data, why is it better to make a graph instead of just looking at the raw data in a table?
marusya05 [52]
In a Data table it doesn’t show increase or decrease while a graph will.
6 0
4 years ago
Read 2 more answers
PLEASE HELP I NEED IT RIGHT NOW
morpeh [17]
The answer should be B :)
7 0
3 years ago
Read 2 more answers
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