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dexar [7]
3 years ago
5

Which best describes how ocean ridges form? A. Decaying materials filter from above, creating ridges. B. Corals grow on a submer

ged rim, forming circular ridges above the water. C. The flat action of the water shears off the top of a seamount, creating a ridge. D. Magma pushes upward from inside the earth and adds new material to the ocean floor, creating a ridge.
Physics
2 answers:
Andrew [12]3 years ago
8 0
The answer is D i think
ruslelena [56]3 years ago
3 0

Answer:

Option (D)

Explanation:

The two plates move in the opposite direction in a divergent type of plate motion as a result of which seafloor spreading takes place where the magma is forced to come out to the surface of the ocean floor. This allows the addition of new materials to the crust, thereby forming the mid-oceanic ridge. This type of plate boundary leads to the formation of volcanoes and deep-focus earthquakes are often generated.

Thus, the mid-oceanic ridge is formed when magma pushes upward and adds new materials to the crust.

Hence, the correct answer is option (D).

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Which method determines the relative age of Earth's sedimentary layers based on their organization?
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Answer:

Relative age-dating involves comparing a rock layer or rock structure with other near-by layers or structures. Using the principles of superposition and cross-cutting relationships, and structures such as unconformities, one can determine the order of geological events.

7 0
3 years ago
A block, M1=10kg, slides down a smooth, curved incline of height 5m. It collides elastically with another block, M2=5kg, which i
erma4kov [3.2K]

Answer:

2.86 m

Explanation:

Given:

M₁ = 10 kg

M₂ = 5 kg

\mu_k = 0.5

height, h = 5 m

distance traveled, s = 2 m

spring constant, k = 250 N/m

now,

the initial velocity of the first block as it approaches the second block

u₁ = √(2 × g × h)

or

u₁ = √(2 × 9.8 × 5)

or

u₁ = 9.89 m/s

let the velocity of second ball be v₂

now from the conservation of momentum, we have

M₁ × u₁ = M₂ × v₂

on substituting the values, we get

10 × 9.89 = 5 × v₂

or

v₂ = 19.79 m/s

now,

let the velocity of mass 2 when it reaches the spring be v₃

from the work energy theorem,  we have

Work done by the friction force = change in kinetic energy of the mass 2

or

0.5\times5\times9.8\times2 = \frac{1}{2}\times5\times( v_3^2-19.79^2)

or

v₃ = 20.27 m/s

now, let the spring is compressed by the distance 'x'

therefore, from the conservation of energy

we have

Energy of the spring =  Kinetic energy of the mass 2

or

\frac{1}{2}kx^2=\frac{1}{2}mv_3^2

on substituting the values, we get

\frac{1}{2}\times250\times x^2=\frac{1}{2}\times5\times20.27^2

or

x = 2.86 m

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Answer:

A) X3Z4

Explanation:

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