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Elena L [17]
3 years ago
6

Acetaldehyde and butanoic acid must have the same

Chemistry
1 answer:
ANTONII [103]3 years ago
7 0

Answer:

dsvcsdc

Explanation:

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In its aqueous solution, 32% of a substance dissociates to release hydroxide ions. Which of the following is true for the substa
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The solution is a weak base. a weak base is that which dissociates partially in aqueous solution to give hydroxide ions as the only negatively charged ions. In the provided information, only 32 %of the substance dissociates thus it is a partial dissociation. Most of the energy is used to break bonds thus the remaining energy is not enough to cause complete dissociation.

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What is the basic principle that is used during the during the structures of compounds​
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A 3.0 M HCl(aq) solution contains a total of
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Molarity = number of moles / volume in liters solution

Answer (3)

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A sample of O2 gas occupies a volume of 571 mL at 26 ºC. If pressure remains constant, what would be the new volume if the tempe
Vlad1618 [11]

Answer: The new volume at different given temperatures are as follows.

(a) 109.81 mL

(b) 768.65 mL

(c) 18052.38 mL

Explanation:

Given: V_{1} = 571 mL,       T_{1} = 26^{o}C

(a) T_{2} = 5^{o}C

The new volume is calculated as follows.

\frac{V_{1}}{T_{1}} = \frac{V_{2}}{T_{2}}\\\frac{571 mL}{26^{o}C} = \frac{V_{2}}{5^{o}C}\\V_{2} = 109.81 mL

(b) T_{2} = 95^{o}F

Convert degree Fahrenheit into degree Cesius as follows.

(1^{o}F - 32) \times \frac{5}{9} = ^{o}C\\(95^{o}F - 32) \times \frac{5}{9} = 35^{o}C

The new volume is calculated as follows.

\frac{V_{1}}{T_{1}} = \frac{V_{2}}{T_{2}}\\\frac{571 mL}{26^{o}C} = \frac{V_{2}}{35^{o}C}\\V_{2} = 768.65 mL

(c) T_{2} = 1095 K = (1095 - 273)^{o}C = 822^{o}C

The new volume is calculated as follows.

\frac{V_{1}}{T_{1}} = \frac{V_{2}}{T_{2}}\\\frac{571 mL}{26^{o}C} = \frac{V_{2}}{822^{o}C}\\V_{2} = 18052.38 mL

8 0
3 years ago
Send Message
Veronika [31]

Answer:co2

Explanation:

7 0
3 years ago
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