Answer:
there are 3 significant figures
Explanation:
do not count the first 2 zeros. only the nimbers after the zero
Answer:
1.209g of MgO participates
Explanation:
In this problem, we have 0.030 moles of MgO that participates in a particular reaction.
And we are asked to solve for the mass of MgO that participates, that means, we need to convert moles to grams.
To convert moles to grams we need to use molar mass of the compound:
<em>1 atom of Mg has a molar mass of 24.3g/mol</em>
<em>1 atom of O has a molar mass of 16g/mol</em>
<em />
That means molar mass of MgO is 24.3g/mol + 16g/mol = 40.3g/mol
And mass of 0.030 moles of MgO is:
0.030 moles MgO * (40.3g/mol) =
<h3>1.209g of MgO participates</h3>
Always use least amount of sig figs possible. So this 9.7 would be (answer): 2 sig figs
Answer:
0.0102 mole
Explanation:
Use and solve proportions for these with x as the unknown value.
Answer:
alpha rays
Explanation:
The alpha rays has the minimum penetration power.
