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Reptile [31]
3 years ago
14

Determine the mass of CO2 gas produced when 8.24 g of NaHCO3 is added to a solution that contains 4.41 g of HCl.

Chemistry
1 answer:
hjlf3 years ago
4 0

The mass of CO₂ gas = 4.312 g

<h3>Further explanation</h3>

Reaction

NaHCO₃ (s) + HCl (aq) → NaCl (aq) + H₂O (aq) + CO₂ (g)

Find limiting reactant

mol NaHCO₃

\tt \dfrac{8.24}{84,007 }=0.098

mol HCl

\tt \dfrac{4.41}{36.5}=0.121

Limiting reactant :  NaHCO₃ (smaller)

mol CO₂ = mol NaHCO₃ = 0.098

mass CO₂ :

\tt 0.098\times 44=4.312~g

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Hello!

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ps: we apply Ka in benzoic acid to the solution.

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\boxed{\boxed{pH = 3.95}}\end{array}}\qquad\checkmark

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I Hope this helps, greetings ... DexteR! =)

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