Determine the mass of CO2 gas produced when 8.24 g of NaHCO3 is added to a solution that contains 4.41 g of HCl.

Chemistry

1 answer:

hjlf3 years ago

4 0

The mass of CO₂ gas = 4.312 g

<h3>Further explanation</h3>

Reaction

NaHCO₃ (s) + HCl (aq) → NaCl (aq) + H₂O (aq) + CO₂ (g)

Find limiting reactant

mol NaHCO₃

$\tt \dfrac{8.24}{84,007 }=0.098$

mol HCl

$\tt \dfrac{4.41}{36.5}=0.121$

Limiting reactant : NaHCO₃ (smaller)

mol CO₂ = mol NaHCO₃ = 0.098

mass CO₂ :

$\tt 0.098\times 44=4.312~g$

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