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MrRa [10]
4 years ago
12

1. A tennis ball is dropped from a second story window. It is in free fall, accelerating downward at a rate of 9.8 m/s2. At the

exact same time, another person throws a tennis ball out the adjacent window with a horizontal velocity of 30 m/s. Assuming no air resistance, which ball hits the ground first? Why?
Physics
1 answer:
inna [77]4 years ago
8 0

Answer:

<h2>Both balls will hit the ground at the same time, because gravity is constant.</h2>

Explanation:

Notice that both balls are being thrown at the same initial height.

It's important to know that these movements which depends of gravity (a constant acceleratio) they would fall at the same rythm, because the gravity is a constant.

Remember that gravity is an acceleration, which it's defined as the change of the velocity, so if both balls change their vertical velocity at the same rate, then they will fall at the same time, because they have the same initial height.

Additionally, when you throw a ball horizontally, it will bend down due to gravity, and this falling movement is the same as if you throw vertically as a free falling movement.

Therefore, both balls will hit the ground at the same time, because gravity is constant.

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A father uses a rope to pull a child on a sled at a constant speed. of the ones listed which forces are present?
Amanda [17]

All the forces may be present.

The child on the sled has a weight- which is due to the force of gravity on the child and the sled.

The sled and the child exert a force on the ground equal to the combined weight of the sled and the child. The ground exerts a normal force on the sled.

The force used by the father to pull the sled is the applied force.

The sled slides on the ground and as a result, the force of friction exists between the ground and the sled, directed opposite to the direction of the motion of the sled.

The father pulls the sled using a rope. As a result, the rope is under Tension.

As the sled moves it also experiences a force of air resistance, which is dependent on the sled's speed.

However, since the father pulls the sled along with constant speed, the sum of all the forces acting on the sled is zero.

Since there is no movement in the upward or downward directions, the weight of the child and the sled is equal to the normal force acted upon the sled by the ground.

The force applied by the father on the rope is equal to the tension in the rope.

Friction and air resistance act opposite to the direction of motion of the sled. for the sled to move at constant speed, the tension in the rope must be equal to the sum of the forces due to friction and air resistance.

4 0
3 years ago
The pressure of 5.0 l of gas increases from 1.50 atm to 1240 mmhg. what is the final volume of the gas, assuming constant temper
garik1379 [7]
First we need to convert everything into SI units.

The initial volume of the gas is (keeping in mind that 1 L = 0.001 m^3:
V_i = 5.0 L = 0.005 m^3

The initial pressure of the gas is (keeping in mind that 1 atm = 1.01 \cdot 10^5 Pa:
p_i = 1.50 atm=1.52 \cdot 10^5 Pa

The final pressure of the gas is (keeping in mind that 760 mmHg = 1 atm=1.01 \cdot 10^5 Pa)
p_f = 1240 mmHg = 1.65 \cdot 10^5 Pa

At constant temperature, the product between pressure and volume of the gas is constant, so we can write
p_i V_i = p_f V_f

from which we find the final volume of the gas:
V_f =  \frac{p_i V_i}{p_f} = \frac{(1.52 \cdot 10^5 Pa)(0.005 m^3)}{1.65 \cdot 10^5 Pa} =0.0046 m^3 = 4.6 L
5 0
3 years ago
If two identical trees are cut down, one with a hand saw, and one with an electric saw...
nataly862011 [7]
The hand saw would involve more work because it takes more time and effort. 
4 0
3 years ago
I need the answer for all of these l don't understand any of this
ElenaW [278]
This should help, 
Search up the Scientific method and lookup for the meaning of each word.
I can't help with all of it but this should help for most 

6 0
4 years ago
In an experiment, a variable, position-dependent force F(x)F(x) is exerted on a block of mass 1.0kg1.0kg that is moving on a hor
leonid [27]

Answer:

The function F(x) for 0 < x < 5, the block's initial velocity, and the value of F(f).

(C) is correct option.

Explanation:

Given that,

Mass of block = 1.0 kg

Dependent force = F(x)

Frictional force = F(f)

Suppose, the following information would students need to test the hypothesis,

(A) The function F(x) for 0 < x < 5 and the value of F(f).

(B) The function a(t) for the time interval of travel and the value of F(f).

(C) The function F(x) for 0 < x < 5, the block's initial velocity, and the value of F(f).

(D) The function a(t) for the time interval of travel, the time it takes the block to move 5 m, and the value of F(f).

(E) The block's initial velocity, the time it takes the block to move 5 m, and the value of F(f).

We know that,

The work done by a force is given by,

W=\int_{x_{0}}^{x_{f}}{F(x)\ dx}.....(I)

Where, F(x) = net force

We know, the net force is the sum of forces.

So, \sum{F}=ma

According to question,

We have two forces F(x) and F(f)

So, the sum of these forces are

F(x)+(-F(f))=ma

Here, frictional force is negative because F(f) acts against the F(x)

Now put the value in equation (I)

W=\int_{x_{0}}^{x_{f}}{(F(x)-F(f))dx}

We need to find the value of \int_{x_{0}}^{x_{f}}{(F(x)-F(f))dx}

Using newton's second law

\int_{x_{0}}^{x_{f}}{(F(x)-F(f))dx}=\int_{x_{0}}^{x_{f}}{ma\ dx}...(II)

We know that,

Acceleration is rate of change of velocity.

a=\dfrac{dv}{dt}

Put the value of a in equation (II)

\int_{x_{0}}^{x_{f}}{(F(x)-F(f))dx}=\int_{x_{0}}^{x_{f}}{m\dfrac{dv}{dt}dx}

\int_{x_{0}}^{x_{f}}{(F(x)-F(f))dx}=\int_{v_{0}}^{v_{f}}{mv\ dv}

\int_{x_{0}}^{x_{f}}{(F(x)-F(f))dx}=\dfrac{mv_{f}^2}{2}+\dfrac{mv_{0}^2}{2}

Now, the work done by the net force on the block is,

W=\dfrac{mv_{f}^2}{2}+\dfrac{mv_{0}^2}{2}

The work done by the net force on the block is equal to the change in kinetic energy of the block.

Hence, The function F(x) for 0 < x < 5, the block's initial velocity, and the value of F(f).

(C) is correct option.

7 0
3 years ago
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