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FromTheMoon [43]

3 years ago

13

Which compound contains only covalent bonds?(1) NaOH (3) Ca(OH)2 (2) Ba(OH)2 (4) CH3OH

1 answer:

pashok25 [27]3 years ago

3 0

Only CH3OH contains convalent bonds. Others are metal. But CH3OH is methanol.

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Answer the question

Ostrovityanka [42]

It is an adaptation

3 0

3 years ago

A solution has a pH of 2.5. What is its [OH-] ?

gulaghasi [49]

POH=14-pH=14-2.5=11.5 pH=-log[H+] 2.5=-log [H+] [H+]=10^-5/2 [OH-]=10^(14-5/2)=10^23/2

8 0

2 years ago

Be sure to answer all parts. What is the [H3O+] and the pH of a buffer that consists of 0.26 M HNO2 and 0.89 M KNO2? (K, of HNO2

Aleksandr-060686 [28]

Answer : The $H_3O^+$ ion concentration is, $1.12\times 10^{-3}M$ and the pH of a buffer is, 2.95

Explanation : Given,

$K_a=7.1\times 10^{-4}$

Concentration of $HNO_2$ (weak acid)= 0.26 M

Concentration of $KNO_2$ (conjugate base or salt)= 0.89 M

First we have to calculate the value of $pK_a$ .

The expression used for the calculation of $pK_a$ is,

$pK_a=-\log (K_a)$

Now put the value of $K_a$ in this expression, we get:

$pK_a=-\log (7.1\times 10^{-4})$

$pK_a=4-\log (7.1)$

$pK_a=3.15$

Now we have to calculate the pH of the solution.

Using Henderson Hesselbach equation :

$pH=pK_a+\log \frac{[Salt]}{[Acid]}$

$pH=pK_a+\log \frac{[KNO_2]}{[HNO_2]}$

Now put all the given values in this expression, we get:

$pH=3.15+\log (\frac{0.89}{0.26})$

$pH=2.95$

The pH of a buffer is, 2.95

Now we have to calculate the $H_3O^+$ ion concentration.

$pH=-\log [H_3O^+]$

$2.95=-\log [H_3O^+]$

$[H_3O^+]=1.12\times 10^{-3}M$

The $H_3O^+$ ion concentration is, $1.12\times 10^{-3}M$

4 0

2 years ago

Cual es el numero de oxidacion de la respiración

Vinil7 [7]

The answer is 0 if im right

3 0

3 years ago

PLEASE HELP ME WILL DO ANYTHING ‼️‼️

deff fn [24]

Answer:

In first shell 2 electrons are present and 7 electrons are present in last shell

Explanation:

6 0

2 years ago