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Alekssandra [29.7K]
2 years ago
10

I need help with nine and 10 I will really appreciate it

Physics
1 answer:
horsena [70]2 years ago
7 0

Answer:

9] V = D ÷ T

Take any distance value from the graph and its relevant time.

V = 4 ÷ 2

V = 2 m/s

[You will notice that any distance values with its time will give you 2 m/s as its speed. This means that speed is constant throughout.]

10] Take the distance value and its time for the highest peak of B.

V = 20 ÷ 2

V = 10 m/s

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The graph below shows the variation with distance r from the nucleus of the square of the wave function, Ψ^2, of a hydrogen atom
Ludmilka [50]

The region a represents the distance of the electron from the nucleus.

According to the wave mechanical model of the atom, the probability of finding an electron within a given volume element (representing the atom) is the square of the wave function psi.

Since a is the region in space where there is the greatest probability of finding the electron in the atom, it follows that distance of the electron form the atom is always a.

Learn more about the wave mechanical model: brainly.com/question/1382157

3 0
3 years ago
Calculate the de broglie wavelength (in picometers) of a hydrogen atom traveling at 440 m/s.
Aleonysh [2.5K]

De broglie wavelength, \lambda = \frac{h}{mv}, where h is the Planck's constant,  m is the mass and v is the velocity.

h = 6.63*10^{-34}

Mass of hydrogen atom,  m = 1.67*10^{-27}kg

v = 440 m/s

Substituting

   Wavelength \lambda = \frac{h}{mv} = \frac{6.63*10^{-34}}{1.67*10^{-27}*440} = 0.902 *10^{-9}m = 902 *10^{-12}m

1 pm = 10^{-12}m\\ \\ So , \lambda =902 pm

So  the de broglie wavelength (in picometers) of a hydrogen atom traveling at 440 m/s is 902 pm

7 0
3 years ago
An ice sheet 5m thick covers a lake that is 20m deep. what is the temperature of the water at the bottom of the lake? explain yo
umka2103 [35]

Answer:

4°C

Explanation:

Water is densest at 4°C.  Since dense water sinks, the bottom of the lake will be 4°C.

5 0
3 years ago
Read 2 more answers
Concrete has a density of 2400kg/m3. Calculate the mass of 150m3 of concrete in kilograms
In-s [12.5K]

Answer:

360,000

Explanation:

This is because the density is per kilogram so you would just multiply 2400 by 150 to give you 360000.

2400*150=360,000

3 0
3 years ago
The 10-lb block has a speed of 4 ft>s when the force of F = (8t2) lb is applied. Determine the velocity of the block when it
Zanzabum

Answer:

The velocity of the block is 231650.8 ft/s

Explanation:

Knowing

W = 10 lb

v0 = u = 4 ft/s

F = 8 t^{2} lb

ms = 0.2

Applying the newton second law

ΣFy = 0

N - W = 0 --> N = W = 10 lb

ΣFx = ma_{x}

F - ms N = ma

8t^{2}- 0.2(10) = \frac{10}{32.2} a

a = 3.22 (8t^{2}  - 2)

Using Kinematics

a = dv/dt

\int\limits^v_u  dv = \int\limits^t_0 {a} \, dt = \int\limits^t_o {3.22 (8t^{2}  - 2)} \, dt

v - 4 = 3.22 (\frac{8}{2} t^{3} - 2t)

when t = 30

v = 231650.8 ft/s

5 0
3 years ago
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