Answer and work is shown in the image attached.
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Answer:
C. 1) No Change (4 sec) 2) 5.7 sec 3) 2.8 sec 4) No Change (4 sec)
Explanation:
Given that:
Period (T) = 4 s
1) If the mass is doubled.
The period of a pendulum is given by the formula:
where L is the length and g is the acceleration due to gravity.
From the formula, the period does not depend on the mass of the spring therefore if the mass is doubled the period does not change.
2) The string length is doubled
Given that:

if the length is doubled, the new spring length is 2L. Therefore the new period (T1) is given as:

3) The string length is halved
Given that:

if the length is halved, the new spring length is L/2. Therefore the new period (T1) is given as:

4) The amplitude is halved
From the formula, the period does not depend on the amplitude therefore if the amplitude is halved the period does not change.
Answer:
Displacement of Mr. Llama: Option D. 0 miles.
Explanation:
The magnitude of the displacement of an object is equal to the distance between its final position and its initial position. In other words, as long as the initial and final positions of the object stay unchanged, the path that this object took will not affect its displacement.
For Mr. Llama:
- Final position: Mr. Llama's house;
- Initial position: Mr. Llama's house.
The distance between the final and initial position of Mr. Llama is equal to zero. As a result, the magnitude of Mr. Llama's displacement in the entire process will also be equal to zero.
1/Rt = 1/R1 + 1/R2 + 1/R3+ 1/R4+ 1/R5
1/Rt = 1/6+ 1/6+1/6+1/6+1/6
1/Rt = 5/6
Rt = 6/5
Rt = 1.2 ohm
so B is the answer