<em>Noun </em>
a substance that takes part in and undergoes change during a reaction.
Answer:
The fertilizer ammonium sulfate, (NH4)2SO4, is prepared by the reaction of ammonia, NH3, with sulfuric acid: 2 NH3 (g) + H2SO4 (aq) (NH4)2SO4 (aq)
How many moles of ammonium sulfate are produced if 1.50 moles of ammonia react completely at STP? Answer: The balanced equation indicates that 2 moles of NH3 react to produce 1 mole of (NH4)2SO4.
1.50 moles NH3 x 1 mol (NH4)2SO4 = 0.750 moles (NH4)2SO4
Explanation:
Answer:
b
Explanation:
The correct answer would be <u>requiring individuals to complete specific types of work.</u>
<em>A question of how to produce deals with the processes of production itself. There are several small processes that eventually aggregate together to lead to the production of goods or services. Some of these small processes will definitely require that individuals within the production unit complete specific types of work.</em>
The option of growing corn instead of potatoes and producing more capital goods and fewer consumer products address what to produce while the option of selling natural resources to other countries has to do with for whom to produce.
Correct option: b
Answer:
Percentage yield = 30%
Explanation:
Given data:
Number of moles of NO = 7.0 mol
Number of moles of O₂ = 5 mol
Number of moles of NO₂ = 3 mol
Percentage yield = ?
Solution:
Chemical equation:
2NO + O₂ → 2NO₂
Now we will compare the moles of NO₂ with NO and O₂ .
NO : NO₂
2 : 2
7.0 : 7.0
O₂ : NO₂
1 : 2
5.0 : 2 ×5.0 = 10 mol
The number of moles of NO₂ produced by NO are less it will be limiting reactant.
Mass of NO₂ = moles × molar mass
Mass of NO₂ = 10 mol × 46g/mol
Mass of NO₂ = 460 g
Actual yield of NO₂:
Mass of NO₂ = moles × molar mass
Mass of NO₂ = 3 mol × 46g/mol
Mass of NO₂ = 138 g
Percentage yield:
Percentage yield = Actual yield/theoretical yield × 100
Percentage yield = 138 g/ 460 g × 100
Percentage yield = 30%
