Answer:
ΔG = -52.9 kJ/mol
Explanation:
Step 1: Data given
Temperature = 298 K
All species have a partial pressure of 1 atm
Δ G ° = − 69.0 kJ/mol
Step 2: The balanced equation
N2(g) + 3H2(g) ⇆ 2NH3 (g)
Step 3: Calculate Q
we will use the expression: ΔG = ΔG° + RT*ln(Q)
⇒with Q = the reaction coordinate: Q = (PNH3)²/ ((PN2)*(Ph2)³) = 666.67
Step 4: Calculate ΔG
So, ΔG = -69.0 kJ/mol + (0.008314 kJ/mol*K)*(298 K)*ln(666.67) = -52.9 kJ/mol
(R = the gas constant = 8.314 J/mol* K OR 0.008314 kJ/mol*K)
Explanation:
In the context, a vial which is used in store medical samples is filled with water at room temperature. And the vial is kept on a cold water. Also a water bag containing warm water is kept near the vial.
The cold water kept at the bottom of the vial is having lower kinetic energy while warm water will have higher kinetic energy than the others. Since the water in the vial is at room temperature and it is in touch with the cold blue water, the water in the vial will loose or give its temperature to the cold blue water through conduction as well as convection process since temperature always flows from a hot body towards the cold body.
On the other hand, the warm water placed next tot he vial will give its temperature to the atmosphere.
Answer:
Methane(CH₄).
Explanation:
- Thomas Graham found that, at a constant temperature and pressure the rates of effusion of various gases are inversely proportional to the square root of their masses.
<em>∨ ∝ 1/√M.</em>
where, ∨ is the rate of diffusion of the gas.
M is the molar mass of the gas.
<em>∨₁/∨₂ = √(M₂/M₁)</em>
<em></em>
- The molar mass of different choices:
Carbon dioxide: 44.01 g/mol.
Water vapor
: 18.0 g/mol.
Ammonia (NH₃): 17.0 g/mol.
Methane(CH₄): 16.0 g.mol.
<em>Since, methane has the lowest molar mass. So, it will diffuse faster within a system.</em>
Answer:
b) [bicarbonate]/[carbonic acid] = 9.4
Explanation:
The pH of a buffer system is given by the Henderson-Hasselbach equation:
- pH = pKa + log ([bicarbonate] / [carbonic acid])
Where pka = -log (Ka) = -log(4.2x10⁻⁷) = 6.38
Now we <u>solve for [bicarbonate] / [carbonic acid]</u>:
- 7.35 = 6.38 + log ([bicarbonate] / [carbonic acid])
- 0.97 = log ([bicarbonate] / [carbonic acid])
= [bicarbonate] / [carbonic acid]
- [bicarbonate] / [carbonic acid] = 9.33 ≈ 9.4
So the answer is b).
There are two ways that I can think of, the first way would be evaporation then condensation or the second way would be a coffee filter.
