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Komok [63]
3 years ago
11

[Ar]4s23d104p3 is the electron configuration of a(n) ________ atom.

Chemistry
2 answers:
Westkost [7]3 years ago
7 0

<u>Answer:</u> The given configuration is of Arsenic atom.

<u>Explanation:</u>

Electronic configuration tells us about the number of electrons that are present in an atom. It also determines the atomic number of an element.

For the given configuration:  [Ar]4s^23d^{10}4p^3

Number of electrons present in argon = 18

So, total number of electrons in the given configuration = 18 + 2 + 10 + 3 = 33

The element having atomic number '33' is Arsenic.

Hence, the given configuration is of Arsenic atom.

madreJ [45]3 years ago
3 0
<span>[Ar]4s23d104p3 is the electron configuration of a(n) __As______ atom.</span>
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Answer:

ΔH° of the reaction is -747.54kJ

Explanation:

Based on gas law, it is possible to find the ΔH of a reaction using ΔH of half reactions.

Using the reactions:

<em>(1) </em>C(graphite) + 1/2O₂(g) → CO(g) ΔH° = -110.5 kJ

<em>(2) </em>CO(g) + 1/2O₂(g) → CO₂(g) ΔH° = -283.0 kJ

<em>(3) </em>H₂(g) + 1/2O₂(g) → H₂O(l) ΔH° = -285.8 kJ

<em>(4) </em>C(graphite) + 2H₂(g) → CH₄(g) ΔH° = -74.81 kJ

<em>(5) </em>CH₄(g) + 2O₂(g) → CO₂(g) + 2H₂O(l) ΔH° = -890.3 kJ

The sum of 4×(4) + (5) gives:

4C(graphite) + 8H₂(g) + 2O₂(g) → CO₂(g) + 2H₂O(l) + 3CH₄(g)

ΔH° = -74.81 kJ ×4 - 890.3 kJ = -1189.54kJ

Now, this reaction - 4×(1) gives:

4CO(g) + 8H₂(g) → CO₂(g) + 2H₂O(l) + 3CH₄(g)

ΔH° = -1189.54kJ - 4×-110.5 = <em>-747.54kJ</em>

<em></em>

Thus <em>ΔH° of the reaction is -747.54kJ</em>

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